Switch case error before to run simulation?
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Hello can some one tell me why i get this mistake when i try to run the simulation?
Output argument 'battery' is not assigned on some execution paths.
Function 'MATLAB Function1' (#131.10.17), line 1, column 11:
"battery"
Launch diagnostic report.
function [battery, load, Emerg] = BattController1(SOC, Vconv)
%#codegen
persistent casevar
if isempty (casevar)
casevar=0;
end
switch (casevar)
% case 0
% if SOC==0 casevar=0;
% battery=0;
% load=0;
% Emerg=0;
% end
case 1
if SOC>=95 casevar=1;
load=1;
battery=0;
Emerg=0;
end
%suppliying load from batteries and disconnect it from PV panels charge in order to avoid overcharges
case 2
if (30<SOC) && (SOC<95) casevar=2;
load=1;
battery =1;
Emerg=0;
end
%suppliying load from batteries and batteries charging
case 3
if (SOC<30) && (Vconv>19) casevar=3;
load=0;
battery=1;
Emerg=1;
else
load=0;
battery=0;
Emerg=0;
end
%battery charging of PV panels and load disconected from batteries
otherwise
load=0;
battery=0;
Emerg=0;
end
3 件のコメント
Walter Roberson
2022 年 5 月 31 日
case 1
if SOC>=95
if you got case 1 but SOC<95 then MATLAB will not look inside case 2 and the others to find matches, and will not activate the otherwise.
You should set the output values to the otherwise choices first, and then after that have your case that will fill in better values sometimes... and if not then the outputs will still be set to 0 or whatever you initialize
採用された回答
Walter Roberson
2016 年 6 月 1 日
Suppose case 1 but SOC < 95, then what will battery be assigned?
2 件のコメント
Stephen23
2016 年 6 月 2 日
編集済み: Stephen23
2016 年 6 月 2 日
@Tony Castillo: read Walter's answer again: consider case 1 and SOC<95, then you do not define the outputs. But you call the function with some outputs, and yet they are not defined... thus the error.
The solution is to define the outputs for every possible permutation of states, or to define some default values once at the beginning of the function.
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