How to spread out an arry of matrix randomly
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I have random matrix like this
[2 2 2 2 1 1 1 1 1 -1 -1 -1 -1 -1]
and depend to the result of calculation number of 2 1 -1 will be different but i want to spread these numbers randomly like this e.g. [2 1 2 -1 1 1 2 -1 2 -1 -1 2 ]
how should i do this?
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回答 (2 件)
Walter Roberson
2016 年 5 月 18 日
YourVector(randperm(length(YourVector)))
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Stephen23
2016 年 5 月 19 日
@Hamid Reza Barzegar: Walter Roberson's answer clearly uses randperm(length(...)). You have written length(randperm(...).
Roger Stafford
2016 年 5 月 18 日
編集済み: Roger Stafford
2016 年 5 月 18 日
Let n be the desired length of the result and let a = [2 1 -1] :
p = randi(3,n,1); % <-- Corrected
v = a(p(randperm(n))); % v is your result % <-- Corrected
5 件のコメント
Roger Stafford
2016 年 5 月 18 日
As I state above, your expression is in error in using "length(randperm(Alloc_Sc))" instead of "randperm(length(Alloc_Sc))".
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