How to rearrange a matrix in a preferred order
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Dear All,
I have a matrix of 40 *3 that is originally is in the numeric order with respect to the first column i.e.
[1 100 234
2 345 890
3 455 111
.
.
.
40 444 555]
However, I would like to rearrange the original matrix based on the following arbitrarily guideline:
[35
20
2
4
1
.
.
39]
Thus, my desired output is a new 40*3 matrix whose first, second and third (and etc) rows are the 35th, 20th and second (and etc) rows of the original matrix. Is there a possible way to rearrange any matrix in the user-defined way as I did in my example above?
Thanks.
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Stephen23
2016 年 5 月 10 日
編集済み: Stephen23
2016 年 5 月 10 日
>> old = randi(9,5,3);
>> old(:,1) = 1:5
old =
1 6 4
2 8 9
3 9 6
4 1 2
5 2 5
>> idx = [2,3,5,1,4];
>> new = old(idx,:)
new =
2 8 9
3 9 6
5 2 5
1 6 4
4 1 2
Using indexing is a very basic MATLAB concept. To learn this kind of basic usage all beginners should do these tutorials:
2 件のコメント
Stephen23
2016 年 5 月 10 日
編集済み: Stephen23
2016 年 5 月 10 日
My answer shows how to rearrange your matrix based on some indices (you call the indices "arbitrary guideline", but in reality they are simply indices):
yourMatrix(theIndices,:)
That is all. Have you tried this yet?
Now you have given some new explanation or requirements, but not very clearly. What does "as you can see the big matrix rearranged in the group of 40 rows based on the guideline matrix" mean ?
How is the output in your comment different to what you asked in your original question?
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