How to split a cell array?

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angelavtc
angelavtc 2016 年 4 月 25 日
コメント済み: angelavtc 2016 年 4 月 30 日
Hello!
Be
Z={'1.1 2.1 3.2 3.3 5.5 5.4'; '3 4 5 10 11 56'};
a 2*1 cell array.How can I split Z into a cell array with 2x6 cells? Notice that Z is composed by numbers.
Thanks a lot.

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Stephen23
Stephen23 2016 年 4 月 25 日
編集済み: Stephen23 2016 年 4 月 25 日
Option One: Convert to Numeric
>> mat = [sscanf(Z{1},'%f'),sscanf(Z{2},'%f')].'
mat =
1.1000 2.1000 3.2000 3.3000 5.5000 5.4000
3.0000 4.0000 5.0000 10.0000 11.0000 56.0000
Best would be to leave it as a numeric array... however if you really need a cell array of numeric scalars, then use num2cell:
num2cell(mat)
Option Two: Keep as String
>> tmp = regexp(Z,'\S+','match');
>> tmp = vertcat(tmp{:})
tmp =
'1.1' '2.1' '3.2' '3.3' '5.5' '5.4'
'3' '4' '5' '10' '11' '56'
  4 件のコメント
Stephen23
Stephen23 2016 年 4 月 26 日
編集済み: Stephen23 2016 年 4 月 26 日
@angelavtc: That example with numeric vectors inside a cell array cannot be trivially converted to a single array with each numeric element in its own cell, because you have different number of elements in each vector. You could try experimenting with these FEX submissions:
Note that you can supply the contents of a cell array by using a comma separated list:
inp = {[...],[...]}
out = padcat(inp{:})
angelavtc
angelavtc 2016 年 4 月 30 日
Thanks a lot!!!

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