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Function Sort to find smallest value in a Column?

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Alessandro
Alessandro 2016 年 2 月 25 日
コメント済み: dpb 2016 年 2 月 25 日
I'm trying to find the five smallest value corresponding to their exact date from this weekly time series. What I wrote is the following:
tsStocks=fints(DATE, SP500)
Five_smallest_Value=sort(tsStocks,1,'ascend')
And i get this error:
Undefined function 'sort' for input arguments of type 'fints'.
Anyone able to tell me the right way to find them?
Thanks in advance.

回答 (1 件)

dpb
dpb 2016 年 2 月 25 日
Don't have Toolbox here so can't try it, but looks like you'll want the sortfts function to deal with a FTSOBJ
  2 件のコメント
Alessandro
Alessandro 2016 年 2 月 25 日
Now at least I don't get the error as before, but sortfts only help me to sort the date from the oldest to the most recent and not, as I would like, to sort the values from the bigger to the smaller or inverse. Thanks for the help.
dpb
dpb 2016 年 2 月 25 日
From the above doc --
Arguments
tsobj
Financial time series object.
flag
(Optional) Sort order:
flag = 1; increasing order (default)
flag = -1; decreasing order
Of course, even if it didn't have the flag optional argument, simply reversing the increasing order after sorting will produce the decreasing order vector.

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