Can anyone help : rank each row of a matrix

2 ビュー (過去 30 日間)
Qian cao
Qian cao 2016 年 2 月 5 日
コメント済み: Jan 2016 年 2 月 14 日
Hi all, If I have a matrix like
A=
0.2 NaN 0.8 0.8
-0.2 1 0.3 0.2
0.2 -0.3 0.2 2
0.7 -0.1 -0.4 0.7
NaN 0.2 NaN 0.9
How do I get a resulting matrix B which ranks each row of A and the result shows like this ... Please Pay attention to row 3. I am looking for a complete answer for this as I am new in Matlab. Thank you a lot !
B=
1 NaN 2 2
1 4 3 2
2 1 2 4
3 2 1 3
NaN 1 NaN 2
  2 件のコメント
Jan
Jan 2016 年 2 月 5 日
You forgot to mention the definition of "ranking". There is an infinite number of possible methods to obtain B based on A.
Stephen23
Stephen23 2016 年 2 月 5 日
Do not post duplicate questions:
You can simply add a comment to your original question.

サインインしてコメントする。

回答 (1 件)

Jan
Jan 2016 年 2 月 5 日
編集済み: Jan 2016 年 2 月 14 日
A guess:
A = [0.2 NaN 0.8 0.8; ...
-0.2 1 0.3 0.2; ...
0.2 -0.3 0.2 2; ...
0.7 -0.1 -0.4 0.7; ...
NaN 0.2 NaN 0.9];
B = nan(size(A));
for k = 1:size(A, 1)
valid = isfinite(A(k, :));
Ak = A(k, valid);
[~, ~, iC] = unique(Ak, 'sorted'); % [EDITED, 3rd instead of 2nd output]
B(k, valid) = Ak(iC);
end
  3 件のコメント
Jan
Jan 2016 年 2 月 9 日
編集済み: Jan 2016 年 2 月 9 日
@Qian cao: Please explain this with any details. Do you get an error message? Are you able to idenitfy the error and fix it by your own?
Did you see, that I asked you for a definition of "ranking"? So please give us a chance to answer efficiently without guessing, what you want and observe.
Jan
Jan 2016 年 2 月 14 日
@Qian cao: What a pitty that you do not answer my question for clarification. Nevertheless, I've edited my answer. Perhaps it is "working" now.

サインインしてコメントする。

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by