Substitute values in an array

Hi guys,

I have a question.

I have an array like this:

d=[1 1 1 1 1 2 2 2 2 2 1 1 1 1 1 ]

How can i substitute the values of the array knowing that for the first 5 positions i want do to d=6 and for the last 4positions i want do do d=8? This means i can´t use d(d==1)= 6 because the values are different for each position...

Can anyone help?

Thanks in advance!

Inês

[Stefan Raab]

Hey, I am not sure if I get you right, but this might solve your problem:

d(1:5) = 6;
d((end-3):end) = 8;

Answer 1

[Stephen23]

If you do not know the indices in advance then you can use diff and find:

>> d = [1,1,1,1,1,2,2,2,2,2,1,1,1,1,1];
>> f = find(diff(d));
>> d(1:f(1)) = 6;
>> d(1+f(end):end) = 8
d =
   6   6   6   6   6   2   2   2   2   2   8   8   8   8   8

Or if the indices are known then they can be hardcoded:

>> d = [1,1,1,1,1,2,2,2,2,2,1,1,1,1,1];
>> d(1:5) = 6;
>> d(11:15) = 8
d =
   6   6   6   6   6   2   2   2   2   2   8   8   8   8   8