フィルターのクリア

function with unknown number of outputs within parfor

3 ビュー (過去 30 日間)
Patrick Mboma
Patrick Mboma 2015 年 8 月 20 日
コメント済み: Patrick Mboma 2015 年 8 月 20 日
Dear all,
I am facing this apparently simple problem: I am trying to write a parfor loop that containts a function call with an unknown number of output arguments. The way I tried to implement it is as follows
Tank=initialize_tank();
parfor ii=1:n
[outputs{:}]=myfunction(a,b,c,d);
Tank(:,ii)=outputs(:);
end
But due to the way variable outputs is used, I get a complaint from parfor. Does anybody know the workaround to this?
Thanks

採用された回答

Edric Ellis
Edric Ellis 2015 年 8 月 20 日
The trick here is that (unfortunately) you need to assign the outputs of your function to a temporary variable, and convince parfor that the variable is indeed a temporary. Like so:
numOut = 3;
n = 7;
out = cell(numOut, n);
parfor idx = 1:n
% This line is required by PARFOR to ensure that 'tmp' is treated
% as a temporary loop variable:
tmp = cell(1, numOut);
% Call the function with a variable number of outputs:
[tmp{1:numOut}] = deal(rand());
% Assign into the output:
out(:, idx) = tmp;
end
Without the tmp = cell(1, numOut); statement, parfor thinks you are assigning to only part of tmp in the following line, and therefore concludes that your loop is order-dependent. By assigning to tmp without any indexing, parfor realises that you are creating a whole new value.
  1 件のコメント
Patrick Mboma
Patrick Mboma 2015 年 8 月 20 日
Edric,
Your solution works very well. Thanks a lot.

サインインしてコメントする。

その他の回答 (1 件)

Matt J
Matt J 2015 年 8 月 20 日
Tank=initialize_tank();
numOutputs=size(Tank,1);
parfor ii=1:n
[outputs{1:numOutputs}]=myfunction(a,b,c,d);
Tank(:,ii)=outputs(:);
end
  4 件のコメント
Matt J
Matt J 2015 年 8 月 20 日
Hmmmm. Well, one solution would be to return just a single argument from myfunction. I.e., have it return "outputs" already in cell array form, like below. Even if you don't want to rewrite myfunction, it should be easy to write a wrapper for it that will do this.
n=10;
a=1;b=1;c=1;d=1;
Tank=initialize_tank(n);
numOutputs=size(Tank,1);
parfor ii=1:n
out=myfunction(a,b,c,d,numOutputs);
Tank(:,ii)=out(:);
end
function T=initialize_tank(n)
T=nan(4,n);
function out=myfunction(a,b,c,d, numOutputs)
out=cell(1,numOuputs);
Patrick Mboma
Patrick Mboma 2015 年 8 月 20 日
Matt,
This workaround using a wrapper function would work brilliantly. Edric, below, proposes an alternative solution but which also requires an extra step. Both solutions work very well. Thank you very much.

サインインしてコメントする。

カテゴリ

Help Center および File ExchangeParallel for-Loops (parfor) についてさらに検索

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by