How to write function in matlab

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Paul
Paul 2015 年 7 月 21 日
編集済み: Paul 2015 年 8 月 11 日
Hi all,
Dose any body knows how to write interpolation function (interp2) instead of using its command on matlab?
Best regards,
  2 件のコメント
John D'Errico
John D'Errico 2015 年 7 月 21 日
There are codes on the file exchange for interpolation. Why not use one of them?
Yes, of course it is possible to write your own interpolation code. But if your goal is to use a home grown code instead of one professionally written, this is a poor choice. And if your goal is to merely learn how to do interpolation, then do some reading. Learn about interpolation methods.
If you have some other obscure reason, then why not tell us? We might be able to offer better advice if we know what you are doing and why.

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回答 (3 件)

Torsten
Torsten 2015 年 7 月 21 日
A starting point :
https://en.wikipedia.org/wiki/Bilinear_interpolation
Best wishes
Torsten.

addou abdeljalil
addou abdeljalil 2015 年 7 月 21 日
m1 =E2(1:4) ; r1 =F2_pixel(1:4) ;
m2 =E2(4:16) ; r2 =F2_pixel(4:16) ;
p1 = polyfit(m1,r1,2) ; % interpolation degre 2
p2 = polyfit(m2,r2,3) ; % interpolation degre 3
y1 = polyval(p1,m1);
y2 = polyval(p2,m2);
plot(E2(1:16),F2(1:16),'o',m1,y1,'r-',m2,y2,'g-')
legend('...');
xlabel ('E2');
ylabel('F2');
title('.......................')
  1 件のコメント
John D'Errico
John D'Errico 2015 年 7 月 21 日
But this is NOT interpolation. It is NOT a replacement for interp2. Not even close.

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Alex Taylor
Alex Taylor 2015 年 7 月 21 日
The relevant question that everyone wants to know the answer to is:
What is your reason for needing to know how to solve this problem without using interp2 in MATLAB?
I think if you answer this question, it will help everyone understand what exactly your requirements are for whatever it is you are doing. Unless there is some compelling reason why you don't want to use interp2, everyone is going to suggest using interp2 because you are unlikely to write a faster or more memory efficient 2-D interpolation routine yourself, especially if you are using a recent version of MATLAB.
I have answered a variation of this question in the past on how to do log-polar transformations of images, in your case it looks like you want a polar->cartesian transformation, but the idea is the same. However, in my answer, I used interp2.
  1 件のコメント
Stephen
Stephen 2015 年 7 月 22 日
What exactly does "interpolation a bit different" mean? Different from what? How should it be different?

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