sin(2*pi) vs sind(360)

15 ビュー (過去 30 日間)
david dang
david dang 2015 年 7 月 13 日
回答済み: Mike Croucher 2022 年 10 月 21 日
Could someone please explain to me why sin(2*pi) gives me non-zero number and sind(360)? Does this have to do with the floating points of pi?

回答 (3 件)

Mike Croucher
Mike Croucher 2022 年 10 月 21 日
If you ever need to compute sin(x*pi) or cos(x*pi), its better to do sinpi(x) or cospi(x). You never explicitly multily x by a floating point approximation ot pi so you always get the results you expect.

Stephen23
Stephen23 2015 年 7 月 13 日
編集済み: Stephen23 2015 年 7 月 13 日
Yes, it is because π is a value that cannot be represented precisely using a finite binary floating point number. This is also shown in the sind documentation:
"Sine of 180 degrees compared to sine of π radians"
sind(180)
ans =
0
sin(pi)
ans =
1.2246e-16
  2 件のコメント
david dang
david dang 2015 年 7 月 13 日
Thanks for the answer. I tried setting pi = sym(pi), but this increased my computation time significantly. Is there any way to perform my computations in radians, without increasing computation time significantly, and obtain the exact solution?
Stephen23
Stephen23 2015 年 7 月 13 日
編集済み: Stephen23 2015 年 7 月 13 日
No.
Unless of course you buy a computer with infinite memory to hold an infinite representation of π and yet can somehow perform operations at the same speed as your current computer.
π is an irrational number. How do you imagine representing an irrational number with a finite floating point value and not getting rounding error? All numeric computations with floating point numbers include rounding errors, and it is your job to figure out how to take this into account. To understand floating point numbers you should read these:

サインインしてコメントする。


Walter Roberson
Walter Roberson 2015 年 7 月 13 日
Yes, it is due to pi not being represented precisely due to the fact that floating point representation is finite.
  2 件のコメント
david dang
david dang 2015 年 7 月 13 日
Thanks for the answer. I tried setting pi = sym(pi), but this increased my computation time significantly. Is there any way to perform my computations in radians, without increasing computation time significantly, and obtain the exact solution?
Torsten
Torsten 2015 年 7 月 13 日
For a numerical computation, sin(pi)=1.2246e-16 should be exact enough.
Best wishes
Torsten.

サインインしてコメントする。

カテゴリ

Help Center および File ExchangeTrigonometry についてさらに検索

タグ

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by