Manipulating cell arrays based on index

6 ビュー (過去 30 日間)
Noah Chrein
Noah Chrein 2015 年 7 月 1 日
コメント済み: Noah Chrein 2015 年 7 月 1 日
how can I manipulate the elements of an array of cells based on index? for a double array, I can just do this:
>> j = zeros(4);
>> j(1:8) = 1;
>> j(9:16) = 8;
>> j
j =
1 1 8 8
1 1 8 8
1 1 8 8
1 1 8 8
However, for a cell array, I cannot
>> j = cell(4,1)
j =
[]
[]
[]
[]
>> j{1:4} = [2 3 4]
The right hand side of this assignment has too few values to satisfy
the left hand side.
I could do this with a for loop easily, but I intend to extend this to a cell with ~400 elements.
After this is figured out, I'd also like to be able to do something based on the index, such as:
j = cell(100,1);
j(1:100) = ones(1:100,1);
  1 件のコメント
Stephen23
Stephen23 2015 年 7 月 1 日
編集済み: Stephen23 2015 年 7 月 1 日
You really need to read the documentation for ones, because providing it with a vector does not make any sense... it does not do what you think it does.
Also you should not use i or j for variable names, as these are both names of the inbuilt imaginary unit.

サインインしてコメントする。

採用された回答

Stephen23
Stephen23 2015 年 7 月 1 日
編集済み: Stephen23 2015 年 7 月 1 日
"However, for a cell array, I cannot"
Of course you can! Cell array indexing is covered here, and is well worth reading:
But it depends what you expect. What you trying to do here is assign one array to the inside of multiple cells. This does not work. But you can allocate four cells to four cells (these are equivalent):
X(1:4) = {1,2,3,4}
X(1:4) = num2cell([1,2,3,4])
Or one cell (containing an array) to four cells:
X(1:4) = {[2,3,4]}
So if you want a cell array where every cell contains the same element, try this:
X = cell(100,1);
X(:) = {ones(100,1)}
  4 件のコメント
Brendan Hamm
Brendan Hamm 2015 年 7 月 1 日
You actually want to use:
j(1:4) = {[2,3,4]} % Index using parenthesis
Noah Chrein
Noah Chrein 2015 年 7 月 1 日
Ah yes, now this works! Thank you!

サインインしてコメントする。

その他の回答 (1 件)

Azzi Abdelmalek
Azzi Abdelmalek 2015 年 7 月 1 日
編集済み: Azzi Abdelmalek 2015 年 7 月 1 日
jj=cell(100,1)
jj(1:100) = num2cell(ones(100,1))
  3 件のコメント
Azzi Abdelmalek
Azzi Abdelmalek 2015 年 7 月 1 日
編集済み: Azzi Abdelmalek 2015 年 7 月 1 日
jj=cell(100,1);
out=cellfun(@(x) ones(100,1),jj,'un',0)
Noah Chrein
Noah Chrein 2015 年 7 月 1 日
Thank you! this works.

サインインしてコメントする。

カテゴリ

Help Center および File ExchangeMatrix Indexing についてさらに検索

製品

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by