MATLAB Answers

help with dynamic variable names set with 'for' incrementer

3 ビュー (過去 30 日間)
Scragmore 2011 年 11 月 27 日
編集済み: Stephen 2016 年 1 月 12 日
I am trying to split up a large numerical dataset into individual days. What I have that works and what I have that failed is;
function [FxStOut, FxStIndex] = FxSt(FxStIn)
%Struct for Forex
UnqDate = unique(FxStIn(:,1));
UnqL = length(UnqDate);
for ii = 1:UnqL
indx = FxStIn(:,1) == UnqDate(ii);
eval(['dataOut.d' num2str(ii) ' = FxStIn(indx, 2:6);']);
%Have tried but died
%dataOut(ii) = FxStIn(indx, 2:6);
%dataOut.d([ii]) = FxStIn(indx, 2:6);
%dataOut.([ii]) = FxStIn(indx, 2:6);
FxStOut = dataOut;
FxStIndex = UnqDate;
Is 'eval' the only way to achieve this, both reading in and out of array. A number/numeral can not be a variable/array name, as I would like;
is this correct.
Can I solve this by using a 3D (:,:,:), however, each depth is a different size (factors different) and I presume that is not allowed.
  2 件のコメント
Stephen 2016 年 1 月 12 日
All of the answers say "avoid eval". Read this to know why eval is a really bad way of programming (that beginners seem to love):



Teja Muppirala
Teja Muppirala 2011 年 11 月 27 日
You are right in that using EVAL to dynamically generate variable names is generally a messy approach that's not very readable, slow, and doesn't scale well.
One alternative is using cell arrays.
Cell arrays let you store differently sized data, for example:
M{1} = [1 2 3]
M{2} = [1 2; 3 4]
M{3} = 'hello'
M{1} + 10
M{2} * 5
  1 件のコメント
David Holdaway
David Holdaway 2012 年 3 月 7 日
Cell arrays appear a great way of doing this! Thanks very much!


その他の回答 (2 件)

bym 2011 年 11 月 27 日
eval can be evil! avoid if possible.

Walter Roberson
Walter Roberson 2011 年 11 月 27 日
Replace your line
eval(['dataOut.d' num2str(ii) ' = FxStIn(indx, 2:6);']);
dataOut.(['d' num2str(ii)]) = FxStIn(indx, 2:6);
or alternately with
dataOut.(sprintf('d%d',ii)) = FxStIn(indx, 2:6);
  1 件のコメント
Scragmore 2011 年 11 月 28 日
Thanks. Shame you cant accept two ans. Your response answered my question directly but Teja's ans gave me an alternative view and solution to my problem that I am going to run with.
Thanks All


Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by