Only Shifting the outer loop
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This is the assignment I was given: he script should assume an m-by-n array A (m, n >= 2) is assigned in the Command Window. The value mover should also be assigned. The script should rotate all of the values on the outer loop of the array by mover spots clockwise and call the output A_out.
Example executions follow:
>> A = [1 2 3 4 5; 6 7 8 9 10; 11 12 13 14 15; 16 17 18 19 20]; mover = 2;
>> script25
A_out =
11 6 1 2 3
16 7 8 9 4
17 12 13 14 5
18 19 20 15 10
So far I have where it shifts by two positions but I don't know how to get the jut the outer loop to shift. Any hints?
A = [1 2 3 4 5; 6 7 8 9 10; 11 12 13 14 15; 16 17 18 19 20]
mover = 2
B = circshift(A,mover,2)
5 件のコメント
Gina Barlage
2015 年 6 月 1 日
Jan
2015 年 6 月 1 日
No, the outerIndices suggested by Matt J are indices, not the values as in your code. Stay at this code:
Values = A(outerIndices)
A(outerIndices) = ...
Now all you have to do is to insert the circshift 'ed Values instead of the "...". You do not need any loops.
Gina Barlage
2015 年 6 月 1 日
Walter Roberson
2015 年 6 月 2 日
Don't shift the indices, shift the content. See where I said "insert the circshift'ed Values"? Values, not indices
Gina Barlage
2015 年 6 月 2 日
回答 (1 件)
As a hint, the following should give you the Linear Indices of the outer edges of the matrix in clockwise order,
I=reshape(1:m*n,m,n);
outerIndices=[I(1,:),I(2:end-1,end).',I(end,end:-1:1),I(end-1:-1:2,1).'];
2 件のコメント
Gina Barlage
2015 年 5 月 31 日
Jan
2015 年 6 月 1 日
Values = A(outerIndices)
A(outerIndices) = ...
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