Formating strings using named tokens

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Vasco
Vasco 2026 年 1 月 22 日
回答済み: Stephen23 2026 年 1 月 22 日
With regexp a struct can be obtained with named tokens where all information about the token names is in the expression (https://nl.mathworks.com/help/matlab/ref/regexp.html#btqhkwj-7)
Example:
str = '01/11/2000 20-02-2020 03/30/2000 16-04-2020';
expression = ['(?<month>\d+)/(?<day>\d+)/(?<year>\d+)|'...
'(?<day>\d+)-(?<month>\d+)-(?<year>\d+)'];
tokenNames = regexp(str,expression,'names');
for k = 1:length(tokenNames)
disp(tokenNames(k))
end
month: '01' day: '11' year: '2000' month: '02' day: '20' year: '2020' month: '03' day: '30' year: '2000' month: '04' day: '16' year: '2020'
I am now looking for the inverse: specify this expression, and fill in the tokens at the correct location.(like formatting in python https://docs.python.org/3/tutorial/inputoutput.html)
I want to do something like:
tokenName.month = '02'
tokenName.day = '20'
tokenName.year = '2020'
sprintf('(?<month>\d+)/(?<day>\d+)/(?<year>\d+)', tokenName)
Results:
2020/20/02
My usecase is that I define pattern in one location in my scripts to parse filenames, and that in a later moment I want to generate comparable filenames. It is very convinient to have to specify that only once, and not twice with slightly different notation.

回答 (2 件)

Star Strider
Star Strider 2026 年 1 月 22 日
I am not exactly certain what you want.
Using an anonymous function is one option --
DMY = @(d,m,y) sprintf('%02d-%02d-%4d',d,m,y);
day = 19;
month = 1;
year = 1807;
str = DMY(day,month,year)
str = '19-01-1807'
.
  1 件のコメント
Vasco
Vasco 2026 年 1 月 22 日
編集済み: Vasco 2026 年 1 月 22 日
See original question for a clarification

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Stephen23
Stephen23 2026 年 1 月 22 日
Given:
tokenName.month = '02';
tokenName.day = '20';
tokenName.year = '2020';
expr = '(?<month>\d+)/(?<day>\d+)/(?<year>\d+)';
You could do:
out = regexprep(expr, '\(\?<(\w+)>[^)]*\)', '${tokenName.($1)}')
out = '02/20/2020'

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