Use string to define variable
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Hello guys!
I am looking for a way to name a variable with a string name that will be changing according to the T and V values
My code is the following:
-------------------------------
T=15; % input variable T
V=1; % input variable V
load('FRF_T15_V1.mat')
load('FRF_T15_V2.mat')
load('FRF_T15_V3.mat')
formatSpec = 'FRF_T%d_V%d';
filename = sprintf(formatSpec,T,V);
x=eval(filename);
XP=(x{3,3});
save ('XP,'XP')
-----------------------------
I would like for variable XP to be assigned according to the input values of T and V, e.g.,
FRF_T15_V1_XP=(x{3,3});
And then save it as
save (' FRF_T15_V1_XP,' FRF_T15_V1_XP ')
Thanks in advance for your help!
Kind regards,
Hugo
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その他の回答 (3 件)
Steven Lord
2025 年 8 月 9 日
1 投票
Can you dynamically create variables with numbered names like x1, x2, x3, etc.? Yes.
Should you do this? The general consensus is no. That Discussions post explains why this is generally discouraged and offers several alternative approaches.
There are many ways to do this. Here's one that shows how to make the format of the T and V values have the same width and will sort based on the value of T in the directory. Just change the '%n.n' to the largest width of your number range:
% for the character array version
fname = @(t,v) ['FRF_T' num2str(t,'%3.3d') '_V' num2str(v,'%2.2d') '_XP'];
for T=[1 3 5]
for V=1:2
fprintf(1,'%s\n', fname(T,V));
end
end
% for the string version
strfname = @(t,v) strcat("FRF_T", num2str(t,'%3.3d'), "_V", num2str(v,'%2.2d'), "_XP");
for T=[1 3 5]
for V=1:2
fprintf(1,'%s\n', strfname(T,V));
end
end
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