How do you change the look of a graph

2 ビュー (過去 30 日間)
Chris Jordan
Chris Jordan 2015 年 5 月 16 日
コメント済み: Star Strider 2015 年 5 月 16 日
  1 件のコメント
Chris Jordan
Chris Jordan 2015 年 5 月 16 日
編集済み: dpb 2015 年 5 月 16 日
The top plot is what my plot is supposed to look like, the bottom is what my plot actually looks like, hoe do I fix this. Here is my code:
distance = [1:1:7];
for x=1:length(distance)
Tension(x)= (w*lc*lp)/(x*sqrt((lp^2)-(x^2)));
end
plot(distance,Tension,'-o')
title('Distance vs. Tension');
xlabel('Distance, (m)');
ylabel('Tension, (N)');
grid on;

サインインしてコメントする。

採用された回答

Star Strider
Star Strider 2015 年 5 月 16 日
I don’t have your constants so I can’t reproduce your exact results. This idea does what you want:
w = 3; % Filling Missing Constants
lc = 5; % Filling Missing Constants
lp = 11; % Filling Missing Constants
distance = [0:1:7];
for x=1:length(distance)-1
Tension(x)= (w*lc*lp)/(x*sqrt((lp^2)-(x^2)));
end
distanceP = [zeros(1,length(distance)-1); distance(2:end)];
TensionP = [Tension; zeros(size(Tension))];
plot(distanceP,TensionP,'-o')
title('Distance vs. Tension');
xlabel('Distance, (m)');
ylabel('Tension, (N)');
grid on;
The ‘distanceP’ and ‘TensionP’ are plot matrices that create the correct x and y coordinates to plot. Their construction is relatively straightforward. Take a look at their structures to understand how they work, specifically how they plot each (x,y) pair. Note that it plots each column of each matrix against the corresponding column of the other, taking advantage of MATLAB using column-major addressing.
  4 件のコメント
Chris Jordan
Chris Jordan 2015 年 5 月 16 日
Thanks a lot.
Star Strider
Star Strider 2015 年 5 月 16 日
My pleasure!

サインインしてコメントする。

その他の回答 (0 件)

カテゴリ

Help Center および File ExchangeNumber Theory についてさらに検索

タグ

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by