How can I find the set of vertices of hexagons which are adjacent to a random point?

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I have a set of hexagons whose blue coordinates are known:
I have a random red point and I need to know the 4 (in some cases it would be 3) points which are immediately adjacent to it. These points are contained in the black box shown for illustration.
I tried to sort the blue points by measuring distances but I keep getting extra points (shown by black arrows) or missing the required points.

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Matt J
Matt J 2024 年 8 月 13 日
編集済み: Matt J 2024 年 8 月 13 日
hex=[ 0 -1.0000
-0.8660 -0.5000
-0.8660 0.5000
0 1.0000
0.8660 0.5000
0.8660 -0.5000
1.7321 -1.0000
0.8660 -0.5000
0.8660 0.5000
1.7321 1.0000
2.5981 0.5000
2.5981 -0.5000
3.4641 -1.0000
2.5981 -0.5000
2.5981 0.5000
3.4641 1.0000
4.3301 0.5000
4.3301 -0.5000] %hexagon points
hex = 18x2
0 -1.0000 -0.8660 -0.5000 -0.8660 0.5000 0 1.0000 0.8660 0.5000 0.8660 -0.5000 1.7321 -1.0000 0.8660 -0.5000 0.8660 0.5000 1.7321 1.0000
<mw-icon class=""></mw-icon>
<mw-icon class=""></mw-icon>
hex=unique(hex,'rows');
given=[1.2,-1];
pts=[given;hex];
DT=delaunayTriangulation(pts);
CL=DT.ConnectivityList;
idx=any(CL==1,2);
idx=setdiff(CL(idx,:),1);
nearest=pts(idx,:)
nearest = 3x2
0 -1.0000 0.8660 -0.5000 1.7321 -1.0000
<mw-icon class=""></mw-icon>
<mw-icon class=""></mw-icon>
plot(hex(:,1),hex(:,2),'x', nearest(:,1),nearest(:,2),'o',given(:,1),given(:,2),'s');
legend Vertices Nearest Given
axis equal padded
  1 件のコメント
Aravind Varma Dantuluri
Aravind Varma Dantuluri 2024 年 8 月 13 日
I just saw your comment now. I noticed you generated the points on your own. Thanks for the effort and answer.

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その他の回答 (1 件)

Mario Malic
Mario Malic 2024 年 8 月 10 日
Hi,
here's some code to give you an idea
X = rand(3,3);
Y = rand(3,3);
pts = [X(:), Y(:)];
distance = squareform(pdist(pts)); % symmetric matrix that contains distances between points
% distance between pt3 and all other pts
[~, idx] = sort(distance(:, 3));
closestPts = idx(2:5) % first one is distance between pt3 and pt3 so we ignore that
  2 件のコメント
Aravind Varma Dantuluri
Aravind Varma Dantuluri 2024 年 8 月 12 日
Thanks for the answer but this doesn't work.
  1. Not all points are not random. Only 1 is. The rest are vertices of hexagon.
  2. Sorting by distance won't work. Take the below example where the random point is blue mark:
We need to get the 4 points marked by the red line. But if we sort by distance, we omit the black mark and get the red mark.
Mario Malic
Mario Malic 2024 年 8 月 12 日
That random point is just an example, it can be arbitrary!

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