how to mirror data and then plot it?
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この 質問 は dpb
さんによってフラグが設定されました
x =0:1:15;
y = tan(x);
plot(x,y)
i hv to mirror data and then plot also .how to do it
9 件のコメント
ramya
2024 年 8 月 8 日
So I understand that you want to mirror along the middle.
Thus
x = 0:1:15;
y = tan(x);
x_new = x;
x_mirrored = fliplr(x_new);
and
y_new = tan(x_mirrored);
Thus the plot obtained will be
figure;
plot(x_new, y_new, 'b', 'DisplayName', 'Symmetric Data');
legend;
xlabel('x');
ylabel('tan(x)');
title('Symmetric Data Plot');
Let me know if this is what was desired.
Aniket
2024 年 8 月 8 日

Something like this ?
a= [1 2 3 4 5 6 7 8 9 10] ;
b=[0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9 0.2 0.3] ;
ix=fix(numel(a)/2);
c=[b(1:ix) fliplr(b(1:ix))];
plot(a,c)
The above keeps the same number of elements as the original; to do your precise example reduces the number of points by one for an even number...your choice as to which would be the intent/need.
You still haven't precisely defined "symmetry about what?" for the original -- about the minimum, perhaps? That kind of thing may be very dependent upon just what the real application is, not just specifically for the one given example.
But a clear and unambiguous definition of just what "symmetrical" means to you is mandatory...
ramya
2024 年 8 月 8 日
dpb
2024 年 8 月 8 日
In that case, don't start a new and seemingly unrelated thread...what's wrong with the Answer @Cris LaPierre provided you there? Why don't you amplify in depth what "symmetry" is supposed to mean for the given data which look anything but as given?
It's not possible to answer a question when the specifications for the solution definition aren't clear...you may have a clear understanding of what you mean, but apparently nobody else here does...
I'm flagging this as duplicated to keep the conversation in one place and as a courtesy to those who responded there with best efforts...
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