Convert vector of numeric values into a vector of equivalent 8-bit 'int8' binary values

Hi,

I am trying to convert a 1x4 numeric vector into the equivalent 8-bit binary 'int8' value which is also a 1x4 vector, however I am creating a 1x8 vector which appears to be the binary value of 8 which is the second element.

So each numeric element I want to convert to it's 8-bit 'int8' binary equivalent and store it in the same element in another vector.

Assuming I have not messed up my Two's Compliment I am expecting the row vector to be displayed as;

[10011110 01111000 01001111 00001000]

Any help would be appreciated.

x = [-98 8 49 120];

y = zeros(1,length(x));

for idx = 1:length(x)
    y = bitget(x(idx),8:-1:1,'int8');
end

disp(y)

     0     1     1     1     1     0     0     0

Answer 1

[dpb]

x = [-98 8 49 120];
cellstr(dec2bin(int8(x)))

ans = 4x1 cell array
    {'10011110'}
    {'00001000'}
    {'00110001'}
    {'01111000'}

[Dan Lardner]

Thanks for that.

I realised also that I applied the Two's Compliment to my positive integers which was a mistake.

I have not used cell arrays before, but I tried to include it in my original solution. It's not as efficient as your implementation.

x = [-98 8 49 120];
y = cell(length(x),1);
for idx = 1:length(x)
    y{idx} = bitget(x(idx),8:-1:1,'int8');
end
disp(y)

    {[1 0 0 1 1 1 1 0]}
    {[0 0 0 0 1 0 0 0]}
    {[0 0 1 1 0 0 0 1]}
    {[0 1 1 1 1 0 0 0]}

[Walter Roberson]

cellstr(dec2bin(int8(x), 8))

would make more sense.