Fill confidence band hexadecimal color
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Hello!
I am plotting a confidence band using fill, and get an error-message when using hecadecimal color:
I have tried with both 'Color' and 'FaceColor' before the hexadecimal color, without it helping. It works when I use a default color such as 'b'.
Also, when trying just to plot the line (not filling), it works with the html-code.
fill([0:hmax, fliplr(0:hmax)], [upper_bounds, fliplr(lower_bounds)], '#7E2F8E', 'FaceAlpha', 0.2, 'EdgeColor', 'none');
Thanks!
4 件のコメント
The FILL documentation states that the C input argument supports "Patch colors, specified as a color name, RGB triplet, vector of colormap indices, or a matrix of colormap indices", and proceeds to give examples of all of those.
I do not see hexadecimal anywhere in that list.
Perhaps you were thinking of the FACECOLOR or EDGECOLOR name-value arguments, which do support hexadecimal:
Ulrikke
2024 年 6 月 16 日
Stephen23
2024 年 6 月 16 日
"it did not work with Facecolor either"
Have you checked the documentation of your installed MATLAB version (i.e. not the online documentation). It is quite possible that hexadecimal was not supported in your installed version.
Ulrikke
2024 年 6 月 16 日
回答 (2 件)
% Define the hexadecimal color
hexColor = '#7E2F8E';
% Convert hex color to RGB triplet
rgbColor = sscanf(hexColor(2:end), '%2x%2x%2x', [1 3]) / 255;
% Define your x and y values
hmax = 10; % Example hmax value
upper_bounds = rand(1, hmax+1) + 1; % Example data for upper bounds
lower_bounds = rand(1, hmax+1); % Example data for lower bounds
% Use fill with the RGB triplet
fill([0:hmax, fliplr(0:hmax)], [upper_bounds, fliplr(lower_bounds)], ...
rgbColor, 'FaceAlpha', 0.2, 'EdgeColor', 'none');
1 件のコメント
Star Strider
2024 年 6 月 16 日
Your approach for converting hex colours to RGB triplets:
% Convert hex color to RGB triplet
rgbColor = sscanf(hexColor(2:end), '%2x%2x%2x', [1 3]) / 255;
never occurred to me.
+1
Didn't recall that working either.
X = [0 0 1 1];
Y = [0 1 1 0];
fill(X,Y,'','facecolor','#7E2F8E');
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