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how to multiply every single element in a matrix to entire of another matrix?

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majid
majid 2024 年 4 月 7 日
編集済み: majid 2024 年 4 月 7 日
Hello.
I want to multiply every single element in a matrix to entire of another matrix.
x = [100,500,900,1300,1700;
120,600,1080,1560,2040;
140,700,1260,1820,2380;
160,800,1440,2080,2720;
180,900,1620,2340,3060];
z = rand (4,20);
I want to multiply 100 to entire z and then 500 and so on... but when each multipication occured saved it in new indexed parameter.
how can I do this?

採用された回答

Paul
Paul 2024 年 4 月 7 日
Here's one option to store each result in a cell array that's the same size as x
x = [100,500,900,1300,1700;
120,600,1080,1560,2040;
140,700,1260,1820,2380;
160,800,1440,2080,2720;
180,900,1620,2340,3060];
%z = rand (4,20);
z = [1 2;3 4]; % small z for example
S = cellfun(@(x) x*z,mat2cell(x,ones(1,size(x,1)),ones(1,size(x,2))),'Uni',false)
S = 5x5 cell array
{2x2 double} {2x2 double} {2x2 double} {2x2 double} {2x2 double} {2x2 double} {2x2 double} {2x2 double} {2x2 double} {2x2 double} {2x2 double} {2x2 double} {2x2 double} {2x2 double} {2x2 double} {2x2 double} {2x2 double} {2x2 double} {2x2 double} {2x2 double} {2x2 double} {2x2 double} {2x2 double} {2x2 double} {2x2 double}
% check
S{1,1} - x(1,1)*z
ans = 2x2
0 0 0 0
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S{3,3} - x(3,3)*z
ans = 2x2
0 0 0 0
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  6 件のコメント
Bruno Luong
Bruno Luong 2024 年 4 月 7 日
編集済み: Bruno Luong 2024 年 4 月 7 日
Shorter
x = [100,500,900,1300,1700;
120,600,1080,1560,2040;
140,700,1260,1820,2380;
160,800,1440,2080,2720;
180,900,1620,2340,3060];
%z = rand (4,20);
z = [1 2;3 4]; % small z for example
S = arrayfun(@(xij) xij*z,x,'Uni',false)
S = 5x5 cell array
{2x2 double} {2x2 double} {2x2 double} {2x2 double} {2x2 double} {2x2 double} {2x2 double} {2x2 double} {2x2 double} {2x2 double} {2x2 double} {2x2 double} {2x2 double} {2x2 double} {2x2 double} {2x2 double} {2x2 double} {2x2 double} {2x2 double} {2x2 double} {2x2 double} {2x2 double} {2x2 double} {2x2 double} {2x2 double}
majid
majid 2024 年 4 月 7 日
thank you for guiding me.

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その他の回答 (2 件)

Steven Lord
Steven Lord 2024 年 4 月 7 日
If you're asking can you dynamically create variables with numbered names like x1, x2, x3, etc.? Yes.
Should you do this? The general consensus is no. That Discussions post explains why this is generally discouraged and offers several alternative approaches.
One such approach is to use pages of a 3-dimensional array.
x = [100,500,900,1300,1700;
120,600,1080,1560,2040;
140,700,1260,1820,2380;
160,800,1440,2080,2720;
180,900,1620,2340,3060];
z = rand (4,20);
zv = reshape(z, 1, 1, []);
result = x.*zv;
To check:
isequal(result(:, :, 42), x.*z(42))
ans = logical
1
  1 件のコメント
majid
majid 2024 年 4 月 7 日
編集済み: majid 2024 年 4 月 7 日
thankyou for answering.

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Bruno Luong
Bruno Luong 2024 年 4 月 7 日
編集済み: Bruno Luong 2024 年 4 月 7 日
x = [100,500,900,1300,1700;
120,600,1080,1560,2040;
140,700,1260,1820,2380;
160,800,1440,2080,2720;
180,900,1620,2340,3060];
%z = rand (4,20);
z = [1 2;3 4]; % small z for example
[mx,nx] = size(x);
[mz,nz] = size(z);
C = mat2cell(kron(x,z),repelem(mz,mx),repelem(nz,nx))
C = 5x5 cell array
{2x2 double} {2x2 double} {2x2 double} {2x2 double} {2x2 double} {2x2 double} {2x2 double} {2x2 double} {2x2 double} {2x2 double} {2x2 double} {2x2 double} {2x2 double} {2x2 double} {2x2 double} {2x2 double} {2x2 double} {2x2 double} {2x2 double} {2x2 double} {2x2 double} {2x2 double} {2x2 double} {2x2 double} {2x2 double}
  1 件のコメント
majid
majid 2024 年 4 月 7 日
編集済み: majid 2024 年 4 月 7 日
thankyou for answering .

サインインしてコメントする。

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