"reshape" does not give column vector entries in output

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Sergio
Sergio 2024 年 3 月 20 日
編集済み: Rushikesh 2024 年 9 月 27 日
Running test_modified.m we obtain the vector entries for the residuals , as a 1x8 vector. However, with either
r = reshape([result{:}].',[],1) % column vector
r = reshape([result{:}].',1,[]) % row vector
I obtain no vector output. It says "Brace indexing is not supported for variables of this type."
What is wrong and how can I correct this?
Thanks
  4 件のコメント
Sergio
Sergio 2024 年 3 月 20 日
Thanks @Dyuman Joshi, but y0 is defined in enzyme.m which is called in test_modified.m
Sergio
Sergio 2024 年 3 月 20 日
編集済み: Sergio 2024 年 3 月 20 日
@Stephen23 good point! In this case, it would be different, and not V = y1(:)-SP(:). With that, I get
V =
3.0146
-1.1146

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回答 (1 件)

Rushikesh
Rushikesh 2024 年 9 月 27 日
編集済み: Rushikesh 2024 年 9 月 27 日
Hello @Sergio,
The error message "Brace indexing is not supported for variables of this type" usually indicates that cell array indexing is being applied to a variable that is not a cell array.
It seems that y0 and y1 are intended to represent concentrations. Since y0 is not defined but is received in the enzyme.m file, I assume you want to pass the defined y1 to the enzyme function as y0. For clarity and simplicity, consider replacing y1 with y0.
The error arises because result is a numeric array, so you should use parentheses () for indexing instead of braces {}.
After making the necessary corrections, your code should look like this:
result = zeros(8,1); % Initialize the correct variable
%Experiment 1
y0 = [2;1]; % Initial condition
dt = 0.01;
T = 1;
k = [5;1];
[SP, ~] = enzyme(y0, k, dt, T); % Capture only necessary outputs
result(1:2) = y0 - SP;
You can apply similar changes for the remaining experiments. To reshape result into a row or column vector, you can use:
r_column = reshape(result, [], 1); % Column vector
r_row = reshape(result, 1, []); % Row vector
Let me know if this helps.

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