It keeps giving me an error on line 4, saying I'm missing input arguments but I have everything defined?

2 ビュー (過去 30 日間)
function root = BisectionRoot(Q,q,R,F,z1,z2)
tol = 1e-6;
err = 1.0;
z = (z1 + z2)/2;
fz = Fun(Q,q,R,F,z);
fz1 = Fun(Q,q,R,F,z1);
fz2 = Fun(Q,q,R,F,z2);
while err > tol
if fz1 < 0.0 & fz2 > 0.0
if fz > 0.0
z2 = z;
else
z1 = z;
end
elseif fz1 > 0.0 & fz2 < 0.0
if fz < 0.0
z2 = z;
else
z1 = z;
end
else
disp('The given interval does not contain the root.');
break;
end
z = (z1 + z2)/2;
err = abs(z - z1);
fz = Fun(Q,q,R,F,z);
fz1 = Fun(Q,q,R,F,z1);
fz2 = Fun(Q,q,R,F,z2);
end
root = z;
end
  4 件のコメント
Stephen23
Stephen23 2024 年 3 月 3 日
"I just pressed the run button once I finished writing it"
So precisely what values do you expect MATLAB to use for the inputs Q,q,R,F,z1,z2 ?
Patrick
Patrick 2024 年 3 月 3 日
Q = 9.4e-6;
q = 2.4e-5;
R=0.1;
F=(Q*q*z) .*((1-z)./(sqrt(z.^2+R.^2)))/(2*epsilon);
epsilon= 0.885e-12;
So would I just add these values to my code?

サインインしてコメントする。

採用された回答

Torsten
Torsten 2024 年 3 月 3 日
移動済み: Torsten 2024 年 3 月 3 日
Q = 9.4e-6;
q = 2.4e-5;
R=0.1;
epsilon= 0.885e-12;
F=@(z)(Q*q*z) .*((1-z)./(sqrt(z.^2+R.^2)))/(2*epsilon);
z1 = 0.5;
z2 = 2;
root = BisectionRoot(F,z1,z2)
function root = BisectionRoot(Fun,z1,z2)
tol = 1e-6;
err = 1.0;
z = (z1 + z2)/2;
fz = Fun(z);
fz1 = Fun(z1);
fz2 = Fun(z2);
while err > tol
if fz1 < 0.0 & fz2 > 0.0
if fz > 0.0
z2 = z;
else
z1 = z;
end
elseif fz1 > 0.0 & fz2 < 0.0
if fz < 0.0
z2 = z;
else
z1 = z;
end
else
disp('The given interval does not contain the root.');
break;
end
z = (z1 + z2)/2;
err = abs(z - z1);
fz = Fun(z);
fz1 = Fun(z1);
fz2 = Fun(z2);
end
root = z;
end

その他の回答 (0 件)

カテゴリ

Help Center および File ExchangePerformance and Memory についてさらに検索

タグ

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by