フィルターのクリア

Creating 25 x 2 matrix with each row range is 20

5 ビュー (過去 30 日間)
NALLARASU KRISH
NALLARASU KRISH 2024 年 2 月 28 日
コメント済み: NALLARASU KRISH 2024 年 2 月 28 日
i want to occupy 1 to 500 in a matrix of size 25x2 with range of each row is 20. First row contains [1 20], second row contains [21 40], and so on until last 25th row containing [481 500]. I asked chat GPT. It suggested me the following code. But it did not go well.
% Define the range and matrix size
range = 1:500;
matrix_size = [25, 2];
% Calculate the values for each row
row_values = reshape(range, [], 20)';
% Create the matrix by repeating the row values
matrix = repmat(row_values(:), 1, matrix_size(2));
% Reshape the matrix to the desired size
matrix = reshape(matrix, matrix_size);
% Display the matrix
disp(matrix);
Pls clarify!

採用された回答

Stephen23
Stephen23 2024 年 2 月 28 日
m = (0:20:499).' + [1,20]
m = 25×2
1 20 21 40 41 60 61 80 81 100 101 120 121 140 141 160 161 180 181 200
  1 件のコメント
NALLARASU KRISH
NALLARASU KRISH 2024 年 2 月 28 日
Its a magic! Tq!! Pls provide in generalized form to make it universal.

サインインしてコメントする。

その他の回答 (0 件)

カテゴリ

Help Center および File ExchangeMatrix Indexing についてさらに検索

タグ

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by