how to automate this manual code containing if else conditons?

1 回表示 (過去 30 日間)
taimour sadiq
taimour sadiq 2024 年 2 月 15 日
編集済み: Les Beckham 2024 年 2 月 15 日
i m creating a data based on values in variable seletion... if first value of selection is 1 it will pick data from Values cell 1 else if if contains 2 then from values cell 2... it works fine in this case but my data may change every time suppose now Selection = [1 1 1 2 2 2 3 3 3 3] and there are there sets of values or next time may b more or less.. how can i automate my code.. kindly guide..

採用された回答

Stephen23
Stephen23 2024 年 2 月 15 日
S = [1 1 1 1 2 2 2 2 2 2];
V{1} = [20 10 40 50 40 30 20 10 20 30];
V{2} = [10 20 30 20 10 30 20 40 20 30];
M = vertcat(V{:});
Z = M(sub2ind(size(M),S,1:numel(S)))
Z = 1×10
20 10 40 50 10 30 20 40 20 30

その他の回答 (1 件)

Les Beckham
Les Beckham 2024 年 2 月 15 日
編集済み: Les Beckham 2024 年 2 月 15 日
Here is one approach. I eliminated the extraneous parameter ini for this example.
I'm not sure I understand the role of the Time vector here. This may not do what you want if the sizes of Time and Selection are not the same.
Time = 1:10;
Selection = [1 1 1 1 2 2 2 2 2 2];
Values{1} = [20 10 40 50 40 30 20 10 20 30];
Values{2} = [10 20 30 20 10 30 20 40 20 30];
Final = zeros(size(Time));
uniqueValues = unique(Selection);
for ii = 1:numel(uniqueValues) %<<< handles any number of unique values in Selection
Final(Selection == uniqueValues(ii)) = Values{ii}(Selection == uniqueValues(ii));
end
disp(Final)
20 10 40 50 10 30 20 40 20 30
  2 件のコメント
taimour sadiq
taimour sadiq 2024 年 2 月 15 日
your Code is fine just one numeric mistake that why i was not getting the desired result.. now its works fine.. Thanks
Final(Selection == uniqueValues(ii)) = Values{1}(Selection == uniqueValues(ii));
should be
Final(Selection == uniqueValues(ii)) = Values{ii}(Selection == uniqueValues(ii));
Les Beckham
Les Beckham 2024 年 2 月 15 日
You are quite welcome. Good catch on that indexing error. I'll fix the answer.

サインインしてコメントする。

カテゴリ

Help Center および File ExchangeMatrix Indexing についてさらに検索

製品


リリース

R2019b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by