Array indices must be positive integers or logical values.
3 ビュー (過去 30 日間)
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Hey, I m trying to do a bissecion method code.
But when trying to give a var fa the value of f(a) it gives me a :'Array indices must be positive integers or logical values.'
Could anyone explain me why please ?
clear;
tol = 10^(-6);
x1= -2:0.01:2;
fx = x1.^2-1-sin(x1);
a=input('Intervalo inferior: ');
b=input('Intervalo superior: ');
fa=fx(a);
Array indices must be positive integers or logical values.
fb=fx(b);
if sign(fa)==sign(fb)
disp('no tiene solucion')
return
end
while (b-a)/2 > tol
c = (a+b)/2;
fc= fx(c);
if sign(a)==sign(c)
a=c;
fa=fc;
else
b=c;
fb=fc;
end
end
c
2 件のコメント
DGM
2024 年 2 月 15 日
a and b are not constrained to being positive nonzero integers, so you can't use them as array indices.
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その他の回答 (1 件)
VBBV
2024 年 2 月 15 日
Matlab arrays are indexed using whole integers, when you give a fractional or decimal values as input it throws such errors
clear;
tol = 10^(-6);
x1= -2:0.01:2;
fx = x1.^2-1-sin(x1)
a=2.7 %input('Intervalo inferior: ');
b=3.2 %input('Intervalo superior: ');
fa=fx(round(a)) % round the input values
clear;
tol = 10^(-6);
x1= -2:0.01:2;
fx = x1.^2-1-sin(x1)
a=2.5; %input('Intervalo inferior: ');
b=3.2; %input('Intervalo superior: ');
fa=fx(a)
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