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What's the point of 'isinf' function ?

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Infinite_king
Infinite_king 2024 年 1 月 5 日
回答済み: Infinite_king 2024 年 1 月 8 日
In MATLAB we can use '==' operator to check whether the given variable is a finite or infinite. I'm wondering is there any advantages of using 'isinf' function ? like improvement in execution time or handling of some execptions. Any information is helpful. Thank you.

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Infinite_king
Infinite_king 2024 年 1 月 8 日
Reason 1:-
As @Paul and @Walter Roberson pointed out, 'isinf' will make it easier to check for inf values when complex numbers are involved.
Note :- I will add more reasons if I come across any in the future.

その他の回答 (1 件)

Matt J
Matt J 2024 年 1 月 5 日
編集済み: Matt J 2024 年 1 月 5 日
For one thing, it covers cases were the inf elements have mixed signs, thus avoiding the overhead of additional operations like abs().
isinf([-inf, 2, inf, 5])
ans = 1×4 logical array
1 0 1 0
  5 件のコメント
Paul
Paul 2024 年 1 月 5 日
As documented: isinf
"If A contains complex numbers, isinf(A) contains 1 for elements with infinite real or imaginary part, and 0 for elements where both real and imaginary parts are finite or NaN."
Infinite_king
Infinite_king 2024 年 1 月 8 日
Thanks for the comments @Paul and @Walter Roberson. I guess that is a good enough reason to use 'isinf' instead of '==' operator.

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