I am trying to get my answer to Display but it wont let me

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Bastian
Bastian 2023 年 12 月 12 日
回答済み: Voss 2023 年 12 月 12 日
syms f(x)
f(x) = (x^3) - (7*x) + 6;
x=solve(f(x)==0,x);
disp('the roots will be',(x))
says error below-
Incorrect number or types of inputs or outputs for function extractCreationTimeDigits.
Error in sym/disp (line 16)
useDigits = extractCreationTimeDigits(X);
Error in Workshop_5_Excercise_3_Pt_1 (line 4)
disp('the roots will be',(x))
>>
  1 件のコメント
Stephen23
Stephen23 2023 年 12 月 12 日
DISP has only one input argument.
syms f(x)
f(x) = (x^3) - (7*x) + 6;
x=solve(f(x)==0,x);
disp(x)

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採用された回答

Dyuman Joshi
Dyuman Joshi 2023 年 12 月 12 日
The function disp accepts only 1 input argument.
If you want to display the roots and the text in the same line, you will have to create a string before using disp, see this example for reference - https://in.mathworks.com/help/matlab/ref/disp.html#btnoykw-1
If you want to display them seperately, you can call disp() twice like this -
syms f(x)
f(x) = (x^3) - (7*x) + 6;
x=solve(f(x)==0,x)
x = 
disp('the roots will be')
the roots will be
disp(x)

その他の回答 (5 件)

Christopher McCausland
Christopher McCausland 2023 年 12 月 12 日
Hi Bastian,
Try replacing
disp('the roots will be',(x))
with
fprintf('the roots will be %d. \n',x)
This should correct the string formating and print as desired.
Christopher

Star Strider
Star Strider 2023 年 12 月 12 日
Another option —
syms f(x)
f(x) = (x^3) - (7*x) + 6;
x=solve(f(x)==0,x);
disp(["the roots will be ",string(x.')])
"the roots will be " "-3" "1" "2"
Note the use of string arrays and the simple transpose, .' operator.
.

Voss
Voss 2023 年 12 月 12 日
syms f(x)
f(x) = (x^3) - (7*x) + 6;
x=solve(f(x)==0,x);
str = sprintf('%s ',x);
str(end) = [];
fprintf('the roots will be [%s]\n',str)
the roots will be [-3 1 2]

Voss
Voss 2023 年 12 月 12 日
syms f(x)
f(x) = (x^3) - (7*x) + 6;
x=solve(f(x)==0,x);
fprintf('the roots will be [%s]\n',strjoin(string(x)))
the roots will be [-3 1 2]

Voss
Voss 2023 年 12 月 12 日
syms f(x)
f(x) = (x^3) - (7*x) + 6;
x=solve(f(x)==0,x);
fprintf('the roots will be [%s]\n',join(string(x)))
the roots will be [-3 1 2]

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