How to reshape data in 4-D array correctly?

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Erfan Lessan
Erfan Lessan 2023 年 11 月 27 日
編集済み: Stephen23 2023 年 11 月 27 日
For debugging purposes, I've loaded the following table data into my MATLAB script, I want to arrange my table data into a 4-d array. x, y, z, w are my independent variables, and v is my dependent variable.
I want to be able to access the data in v through my 4d array in the following fashion: v_reshaped(1,1,1,1) = 1, v_reshaped(1,1,1,2) = 2, v_reshaped(1,1,2,1) = 3
However, with the script I've written, the data appears as follows: v_reshaped(1,1,1,1) = 1, v_reshaped(1,1,1,2) = 9, v_reshaped(1,1,2,1) = 5
I've put my MATLAB script here for reference, can you show me how I can get the reshaped data in the order I want?
Below is an image of my table:
I've written the following MATLAB script:
% Clear everything
clear all; close all;
% Read table from MATLAB
btable = readtable('binary_lut_test.xlsx');
x.val = btable.x; y.val = btable.y;
z.val = btable.z; w.val = btable.w;
v.val = btable.v;
% Unique values from table
x.uni = unique(x.val); y.uni = unique(y.val);
z.uni = unique(z.val); w.uni = unique(w.val);
v.uni = unique(v.val);
% Create and n-dimensional grid
[X, Y, Z, W] = ndgrid(x.uni, y.uni, z.uni, w.uni)
% Compute expected number of elements
expectedNumel = numel(x.uni) * numel(y.uni) ...
* numel(z.uni) * numel(w.uni); % Evaluates
% to 16
% Reshape data
V.a = reshape(v.val, [numel(x.uni), numel(y.uni),...
numel(z.uni), numel(w.uni)]);

回答 (1 件)

Stephen23
Stephen23 2023 年 11 月 27 日
編集済み: Stephen23 2023 年 11 月 27 日
You can use PERMUTE like this:
v = 1:16;
z = permute(reshape(v,[2,2,2,2]),[4,3,2,1]);
z(1,1,1,1)
ans = 1
z(1,1,1,2)
ans = 2
z(1,1,2,1)
ans = 3

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