Any suggestion to replace the diagonal values of matrices in a 3D array?
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Any suggestion to replace the diagonal values of matrices in a 3D array?
in case1 to "0"
in case1 to "NaN"
e.g. for NaN
M_3D=randi(100, 4,4,3); %fake input
N=size(M_3D,1);
mask=1:N+1:end)=nan;
M_3D=M_3D.*mask;
4 件のコメント
Steven Lord
2023 年 11 月 6 日
One possibility is points at subscripts n*ones(1, ndimsOfArray) for n = 1:min(size(theArray)). Once you reach any "edge" of the array you stop.
So for an array of size (4, 3, 5) those would be the elements at subscripts (1, 1, 1), (2, 2, 2), and (3, 3, 3). That matches conceptually the behavior of the diag function on non-square matrices.
A = reshape(1:12, 3, 4)
diag(A) % (1, 1), (2, 2), and (3, 3) since min(size(A)) is 3.
採用された回答
Dyuman Joshi
2023 年 11 月 6 日
Replacing diagonal values of each 2D matrix of a 3D matrix with NaN
M = randi(100, 4,4,3); %fake input
N = eye(size(M,[1 2]));
M(M&N)=NaN
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