How to replace a line in a text file?

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Ali Almakhmari
Ali Almakhmari 2023 年 9 月 19 日
編集済み: dpb 2023 年 9 月 19 日
How can I use fprintf to write a sentence/string in a text file on a specific line in the text file?

回答 (1 件)

dpb
dpb 2023 年 9 月 19 日
text files are sequential files and can't easily be written to in the middle...in MATLAB, the simplest thing to do will be to read the existing file into memory (readlines will return a string array), make the necessary/wanted modifications in memory to that array and then rewrite the file (or make a new one) with writelines
Alternatively, you can process the file line by line with fgets, modify/pass thru each line in turn and rewrite with fwrite(*). If new line is to be inserted, the code needs to know what that is to be and at which line it should be inserted (or similarly, be able to know/skip rewriting any line(s) that aren't to be in the new file.
But, doing it in place in the existing file is just not the practical way to approach the problem.
(*) I've posted sample filter doing this at least once before but I don't have a link to it at hand; maybe a search for @fgetl and "filter" might find it...
  3 件のコメント
Voss
Voss 2023 年 9 月 19 日
編集済み: Voss 2023 年 9 月 19 日
str = readlines(filename);
str(6826:5:end) = strrep(str(6826:5:end),"2021","2022");
writelines(str,filename);
dpb
dpb 2023 年 9 月 19 日
編集済み: dpb 2023 年 9 月 19 日
If it just happens that the year number 2021 starts at line 6826 in the file and there are four lines between it and the next, but not a year number in those that would match, then you could generalize the string replacement to just replace 2021 with 2022.
str= strrep(str,"2021","2022");
would be the same under those conditions.
If there were other instances of "2021" that were NOT to be changed, then would need the additional logic, yes.
You might find pattern of value here to be able to write a specific search/replace expression that does only the specific instances wanted in more general terms than counting lines.

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