More multiplication operations require less time
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I would expect the execution times for the 3 operations below to get longer and longer. Where have I misled myself? Is it an issue with tic/toc as the timing method, or something else?
A=rand(500,500,500);
tic;
A.*A;
toc;
tic;
A.*A.*A;
toc;
tic;
A.*A.*A.*A.*A.*A;
toc;
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Walter Roberson
2023 年 8 月 29 日
It is because you are not recording the output.
I introduced T0 here because I was noticing that in my tests, T1 (the first operation) was consistently slower than T2 (the second operation), and I suspected that time to parse or something similar was being allocated against the first operation. With the T0 introduced, the measured time for A.*A reduces.
A=rand(500,500,500);
tic;
T0 = A;
toc;
tic;
T1 = A.*A;
toc;
tic;
T2 = A.*A.*A;
toc;
tic;
T3 = A.*A.*A.*A.*A.*A;
toc;
8 件のコメント
Walter Roberson
2023 年 8 月 30 日
Oh, right, it makes sense for James to have done that work! (But it would also have made sense for John to have done it as part of his high precision packages.)
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