Masking images/matrixes
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לק"י
Hello!
I got an image of some stained cells:
![](https://www.mathworks.com/matlabcentral/answers/uploaded_files/1434198/image.png)
And I have a grayscale mask such as this:
![](https://www.mathworks.com/matlabcentral/answers/uploaded_files/1434203/image.png)
(different shades are covering different cells as you can see).
I want to systematically go through each gray shade in the mask and to extract (or leave) the area in the cells image.
I looked up for a quick command, but haven't found one.
I tried to use find command, but I get vectors as a result and can't use it to "talk" with the original image matrix.
This is the code I'm using:
img=imread("4.7.23 ut cd4_prfrn acd3+11002c3.tif");
mask=imread("4.7.23 ut cd4_prfrn acd3+11002c3_cp_masks.png");
i=max(max(mask))
maskx=[];
masky=[];
[maskx, masky]=find(mask==i);
imgmasked=img(maskxy,masky)
(I'm using a for loop to go through all indexes, but it will come later, I want to succeed masking right now)
What is the right way to handle this problem please?
Thanks,
Amit.
2 件のコメント
回答 (1 件)
Image Analyst
2023 年 7 月 14 日
It looks like your mask is actually a labeled image since each blob seems to have a unique value (label). So in that case to get the area of each labeled blob you'd simply do
props = regionprops(labeledImage, 'Area');
allAreas = [props.Area] % Will give a vector of 5 areas.
5 件のコメント
Matt J
2023 年 7 月 18 日
Yes,
imgthldtmp=zeros(size(imgmask));
thldfnd= imgfltrd>(thldmltplr(k)*pxllstavg);
imgthldtmp(thldfnd)=imgfltrd(thldfnd);
Image Analyst
2023 年 7 月 18 日
Heck no. Shorter would be even more cryptic and hard to follow than it is now. No comments, cryptic variable names, etc. I don't know what you did but whatever, if it works for you, fine.
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