Looping for cell arrays

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Davindra Usov
Davindra Usov 2023 年 4 月 25 日
コメント済み: Stephen23 2023 年 5 月 1 日
I have a 3x11 cell array called down_files where each entry in the array is a filename and each of the rows corresponds to a different value for an angle. For example, row 1 corresponds to angle 1, row 2 to angle 2 and so on. The code below worked when the cell array was 1x11, but now that I have added two more rows to it I need to work for 3x11.
lengths_arr contains values read from each file. So lengths_arr should end up being a 3x11 matrix with each row corresponding to the correct angles again (row 1 for angle 2, row 2 for angle 2.......)
for i = 1:length(down_files)
file_data = fileread(down_files{i})
f = regexp(file_data, 'length(\d+)?)', 'tokens') % ignore. this is just getting the length values from the files
if ~isempty(f)
L = str2double(f{1})
lengths_arr(end + 1) = L
many thanks
  1 件のコメント
Stephen23 2023 年 5 月 1 日
Note that by using a look-around you can avoid one layer of the output's nested cell arrays:
f = regexp(file_data, '(?<=length)\d+)', 'match')


回答 (1 件)

chicken vector
chicken vector 2023 年 4 月 25 日
Add a second loop for the rows:
for row = 1 : size(down_files,1)
for col = 1 : size(down_files,2)
  2 件のコメント
Adam Danz
Adam Danz 2023 年 5 月 1 日
lengths_arr(row, col) = L



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