Average values with nan value

26 ビュー (過去 30 日間)
JAVAD
JAVAD 2023 年 3 月 16 日
コメント済み: Adam Danz 2023 年 3 月 22 日
Hi
I have a matrix with 3 dimentions; i,j,t(time).
I try to calculate mean value for each time step but the matter is we have some nan-values. I have four basins and decide to calculate avrage for each basin seperately. It doesnot work properly
............................................
for t= 1:length(time)
if j>85
U1(t)=nanmean(Uwind,'all')
else if j>65 & j<85
U2(t)=nanmean(Uwind,'all')
else if j>25 & j<65
U3(t)=nanmean(Uwind,'all')
else
U4(t)=nanmean(Uwind,'all')
end
end
end
end

採用された回答

Antoni Garcia-Herreros
Antoni Garcia-Herreros 2023 年 3 月 16 日
Not exacty sure what you mean by U1(t). I you want to calculate the mean (excluding NaNs) for each timestep for all i and a specified range of j this should work.
U4=nanmean(Uwind(:,1:25,:),[1,2]);
U3=nanmean(Uwind(:,26:64,:),[1,2]);
U2=nanmean(Uwind(:,65:84,:),[1,2]);
U1=nanmean(Uwind(:,65:end,:),[1,2]);
  1 件のコメント
Adam Danz
Adam Danz 2023 年 3 月 22 日
Instead of nanmean, use mean with the omitnan flag.
For example,
U4 = mean(Uwind(:,1:25,:),[1,2],'omitnan');
mean has more capabilities such as supporting tall arrays, GPU arrays, and code generation, works better with tables, etc. nanmean is discouraged starting in MATLAB R2020b.

サインインしてコメントする。

その他の回答 (1 件)

Cameron
Cameron 2023 年 3 月 16 日
myArray = nan(8,1); %array of nan values
indx = 1:2:7; %index to populate that array
myArray(indx,1) = rand(length(indx),1) %have some nan and some numbers
myArray = 8×1
0.1698 NaN 0.0233 NaN 0.8454 NaN 0.6111 NaN
mean(myArray(~isnan(myArray))) %take the average of only the numbers
ans = 0.4124

カテゴリ

Help Center および File ExchangeCreating and Concatenating Matrices についてさらに検索

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by