Mask with a for loop

I wrote this code that is finding the data i want to remove, i dont know how to mask to remove it from the original vector

vec = [2 3 0 0 7 8 0]

the answer is supposed to be [2 0 0 7 0]

but im getting [3 8], the opposite of what I want, how do i mask to flip this

function [newVec] = removeData(vec)
newVec = [];
for x = 1:length(vec) %don't have to go backwards because we aren't deleting
    if vec(x) ~= 0 && vec(x + 1) == 0%checking for not evens
        newVec = [newVec vec(x)];
    end
end
end

Answer 1

[David Hill]

removeData([2 3 0 0 7 8 0])

ans = 1×5

2 0 0 7 0

function [newVec] = removeData(vec)
newVec = zeros(size(vec));
for x = 1:length(vec) %don't have to go backwards because we aren't deleting
    if vec(x) ~= 0 && vec(x + 1) == 0%checking for not evens
        newVec(x)=1;
    end
end
newVec=vec(~newVec);
end

Answer 2

[Matt J]

removeData([2 3 0 0 7 8 0])

ans = 1×5

2 0 0 7 0

function newVec = removeData(vec)

       newVec = vec;
       newVec(  vec(1:end-1) & ~vec(2:end)  )  = [];

end

Answer 3

[Voss]

removeData([2 3 0 0 7 8 0])

ans = 1×5

2 0 0 7 0

function vec = removeData(vec)
x = 1;
while x < numel(vec)
    if vec(x) ~= 0 && vec(x + 1) == 0%checking for not evens
        vec(x) = [];
    else
        x = x + 1;
    end
end
end