Unique concatenation of multi-dimensional cell arrays
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I have 15, k x k x k cell arrays, stacked ontop of each other ,where each cell contians a row vector. I would like to concactenate each row vector living in the living the the same poisition cell for all 15 cell arrays such that each of the row vectors doesn't have any repetitions
For the sake of clarity, suppose we have only two cell arrays of size 3 x 3,
A(:,:,1) = {[1;2;3],[],[3];
[],[],[4];
[],[2;3],[]}
A(:,:,2) = {[2;3;4],[4],[3];
[],[],[4];
[],[2;4],[]}
%I'd like the output to be
C = {[1;2;3;4],[4],[3];
[],[],[4];
[],[2;3;4],[]}
%This is possible to do with a for loop where each step of the for loop
%looks like
C{i} = unique(cat(1,A{i},B{i}))
However, since k can be fairly large and vectors in each cell are very large this turns out to be very inefficent for me. I don't suppose anyone knows of a quick way to do this? Many Thanks.
Edit the uniqueness is no longer an issue since if say we are able to perform the concactenation to obtain;
D = {[1;2;3;1;2;3;4],[4],[3;3];
[],[],[4;4];
[],[2;2;3;4;4],[]}
C = cellfun(@(x)unique(x), D, 'UniformOutput', false);
What still remains unsolvable to me is how one could obtain D from A. I should add that I have tried
cat(1,A(:,:,1),A(:,:,2))
cat(2,A(:,:,1),A(:,:,2))
cat(3,A(:,:,1),A(:,:,2))
none of which yeild the desired result.
0 件のコメント
採用された回答
Matt J
2023 年 3 月 7 日
A(:,:,1) = {[1;2;3],[],[3];
[],[],[4];
[],[2;3],[]};
A(:,:,2) = {[2;3;4],[4],[3];
[],[],[4];
[],[2;4],[]};
C = cellfun(@union,A(:,:,1),A(:,:,2),'UniformOutput',false)
その他の回答 (1 件)
Voss
2023 年 3 月 7 日
A(:,:,1) = {[1;2;3],[],[3];
[],[],[4];
[],[2;3],[]};
A(:,:,2) = {[2;3;4],[4],[3];
[],[],[4];
[],[2;4],[]};
C = cellfun(@(a,b)unique([a;b]),A(:,:,1),A(:,:,2),'UniformOutput',false)
2 件のコメント
Stephen23
2023 年 3 月 8 日
"Do you have anysuggestions as to where I could read more about this?"
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