compensate vector into same length

if we have multiple vectors, A,B,C. Each of them has different length. How can we compensate them by NaN into same length and store them as a matrix.

Answer 1

[Stephen23]

The simplest approach is to download the function PADCAT() here:

https://www.mathworks.com/matlabcentral/fileexchange/22909-padcat

and use it like this:

M = padcat(A,B,C)

[mingcheng nie]

Thank you for your answer! Really appreciate!

Indeed, I will receive a vector from a function, and I want to compensate it into a certian length. For example, I have a loop for 4 times, within each loop I will get a vector, then I need to compensate the vector with NaN within that loop; then in next loop I will have new vector to compensate.

Or to say, I can NOT have A, B , C ,D vector at one time, and I need to compensate all of them....

maybe I can set a vector ' S' with all NaN and enough length, then within each loop, I compensate A/B/C/D with S.

[Stephen23]

"For example, I have a loop for 4 times, within each loop I will get a vector, then I need to compensate the vector with NaN within that loop; then in next loop I will have new vector to compensate."

How will you know what length to pad to, if you do not have all of the vectors?

I suspect that you could simply store all of the vectors in a cell array, and then supply them to PADCAT after the loop. This would likely be the simplest approach:

N = 4;
C = cell(1,N); % preallocate!
for k = 1:N
    V = your code that generates a vector;
    C{k} = V;
end
M = padcat(C{:})

[mingcheng nie]

Yes you are right and your solution is the straightforward and simple!!! Thanks Stephen, it really helps me!!!!