Solve for Nonlinear State Space Equation

Trying to derive the Nonlinear steady state equation for a double pengelum. Solved for matrix [theta1;theta1dot;theta2;theta2dot]. Need in terms of [theta1dot;theta2doubledot;theta2dot;theta2doubledot]. Where theta1dot and theta2 dot would just be the variable but theta1doubledot and theta2doubledot would the values factored out of the respective equations.
solving for eqn 17 have matrix 18
output for equation 17 in terms of 20
clear; clc;
% Initalize variables
syms theta1(t) theta2(t) r1 r2 m1 m2 g u
% Initalize kinematic constraints
x1 = r1*sin(theta1);
y1 = -r1*cos(theta1);
x2 = x1+r2*sin(theta2+theta1);
y2 = y1-r2*cos(theta2+theta1);
% Initalize velocity equations
x1dot=diff(x1);
y1dot=diff(y1);
x2dot=diff(x2);
y2dot=diff(y2);
% Solve for potential energy
pe=m1*g*y1+m2*g*y2;
%Solve for kinetic energy
ke=1/2*m1*(x1dot^2+y1dot^2)+1/2*m2*(x2dot^2+y2dot^2);
simplify(ke);
% Solve for L=KE-PE
l=ke-pe;
simplify(l);
% Initalize variables
syms theta1dot theta2dot
% Solve for partial derivitive of L by theta1dot
eqn1=subs(diff(subs(l(t), diff(theta1(t)), theta1dot), theta1dot), theta1dot, diff(theta1(t)));
eqn1=simplify(eqn1);
% Solve for the time derivative of eqn1
eqn1=diff(eqn1);
eqn1=simplify(eqn1);
% Solve for partial derivitive of L by theta1
a=simplify(diff(l,theta1));
% Solve for first equation of motion
eqn1=simplify(eqn1-a)-u
eqn1(t) = 
% Solve for partial derivitive of L by theta2dot
eqn2=subs(diff(subs(l(t), diff(theta2(t)), theta2dot), theta2dot), theta2dot, diff(theta2(t)));
eqn2=simplify(eqn2);
% Solve for the time derivative of eqn2
eqn2=diff(eqn2);
eqn2=simplify(eqn2);
% Solve for partial derivitive of L by theta2
z=simplify(diff(l,theta2));
% Solve for second equation of motion
eqn2=simplify(eqn2-z)
eqn2(t) = 
[V,S] = odeToVectorField(subs(eqn1),subs(eqn2));
S=[S(3);S(4);S(1);S(2)]
S = 
V=[V(3);V(4);V(1);V(2)]
V = 

6 件のコメント

Walter Roberson
Walter Roberson 2022 年 12 月 6 日
What is your question?
Cason Cox
Cason Cox 2022 年 12 月 6 日
How to you isolate theta1doubledot in eqn1 and theta2doubledot in eqn2?
Walter Roberson
Walter Roberson 2022 年 12 月 6 日
I do not see any theta1doubledot in your code?
Torsten
Torsten 2022 年 12 月 6 日
I think
d^2/dt^2 theta1(t)
d^2/dt^2 theta2(t)
are meant.
But it's already solved for them after applying "odeToVectorField", isn't it ?
Cason Cox
Cason Cox 2022 年 12 月 6 日
Sorry, yes that is what I meant.
"odeToVectorField" solved for [theta1(t); d/dt theta1(t); theat2(t); d/dt theta2(t)] but I am trying to solve for the matrix with [d/dt theta1(t); d^2/dt^2 theta1(t); d/dt theta2(t); d^2/dt^2 theta2(t)]
Torsten
Torsten 2022 年 12 月 7 日
You are mistaken. "odeToVectorField" solved for d/dt theta1(t) , d^2/dt^2 theta1(t), d/dt theta2(t) , d^2/dt^2 theta2(t).
If it could solve theta1(t) and theta2(t), you wouldn't have to integrate the equations using an ODE integrator (the call to which is missing in your code) - you already had the solution.

サインインしてコメントする。

回答 (0 件)

カテゴリ

ヘルプ センター および File ExchangeNumerical Integration and Differential Equations についてさらに検索

製品

リリース

R2020b

質問済み:

2022 年 12 月 6 日

コメント済み:

2022 年 12 月 7 日

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by