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How to create row vector or 3-D array

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DoinK
DoinK 2022 年 11 月 14 日
編集済み: DoinK 2022 年 11 月 16 日
I want to create row vector that can be multiplied to a matrix.
First, let me explain the matrix.
A_0 is square matrix of order 4*N*(M+1).
A_0=[A_00 A_01 0 0;
A_10 A_11 A_12 0;
A_20 A_21 A_22 A_23;
A_30 A_31 A_32 A_33].
Every matrix in A_0 are square matrix of order N*(M+1).
So i want to create this kind of row vector:
p^(i) with i=0, i get p^(0) %^(i) is not rank, its just index, so p^(0) !=1
p^(i)=(p_(4i)^(i), p_(4i+1)^(i), p_(4i+2)^(i), p_(4i+3)^(i)), %p^(i) has 4*N*(M+1) elements
where
p_j^(i)=(p_(j,0,1)^(i),p_(j,0,2)^(i),...,p_(j,0,N)^(i),
p_(j,1,1)^(i),p_(j,1,2)^(i),...,p_(j,1,N)^(i),...,
p_(j,M,1)^(i),p_(j,M,2)^(i),...,p_(j,M,N)^(i)) i,j>=0 , 4i<=j<=4i+3.
I need to multiply p^(0) * A_00.
For example,
p^(0)*A_0=(p_(0)^(0), p_(1)^(0),p_(2)^(0),p_(3)^(0))*[A_00 A_01 0 0;
A_10 A_11 A_12 0;
A_20 A_21 A_22 A_23;
A_30 A_31 A_32 A_33].
Assume N=3 M=4,
p_(0)^(0) * A_00=
(p_(0,0,1)^(0),p_(0,0,2)^(0),p_(0,0,3)^(0),
p_(0,1,1)^(0),p_(0,1,2)^(0),p_(0,1,3)^(0),
p_(0,2,1)^(0),p_(0,2,2)^(0),p_(0,2,3)^(0),
p_(0,3,1)^(0),p_(0,3,2)^(0),p_(0,3,3)^(0)),
p_(0,4,1)^(0),p_(0,4,2)^(0),p_(0,4,3)^(0)) have N*(M+1)=15 elements and A_00 has N*(M+1) elements too so it can be multiplied.
For the code, i only know how to make row vector of 1 row and N column:
p=sym('p',[1 N]) .
So, i have to make p^(0)=(p_(0)^(0), p_(1)^(0),p_(2)^(0),p_(3)^(0)) that can be open up again to have N*(M+1) elements.
I only need p^(0) because from my equation, the formula to search p^(n)=p^(0)*R %where R is square matrix of order 4*N*(M+1).
  5 件のコメント
Jan
Jan 2022 年 11 月 14 日
What do you call an "infinite matrix"? Do you mean a matrix ith an infinite number of elements? This would need an infinite amount of RAM.
DoinK
DoinK 2022 年 11 月 14 日
Ah you are right Sir, let me edit the question again.

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