conatinate matrix which is getting updated in loop
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hi,
for s=1:500
consall1(s,:,:)=[cons1, cons2, cons31, cons32, cons33, cons34];
end
from above mentioned for loop.I need a single matrix with 6 rows.please reply with your ideas.
sita
4 件のコメント
Michael Haderlein
2015 年 3 月 18 日
So besides the needless introduction of a third dimension, what is wrong with your code fragment? I assume that you cannot vectorize the calculation of cons1,...34. To speed up a bit (though it won't make a big difference here), you can preallocate consall1 with
consall1=zeros(500,6);
and then start overwriting the zeros with the values in the loop.
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