現在この質問をフォロー中です
- フォローしているコンテンツ フィードに更新が表示されます。
- コミュニケーション基本設定に応じて電子メールを受け取ることができます。
May I ask how I can get the 95% confidence intervals for the true mean data?
4 ビュー (過去 30 日間)
古いコメントを表示
Chris
2022 年 10 月 22 日
"A" is data with 700*1 matrix.
I want to have the 95% confidence intervals for the true mean of A.
What codes do I have to use?
Thanks
13 件のコメント
John D'Errico
2022 年 10 月 22 日
編集済み: John D'Errico
2022 年 10 月 22 日
How is this a question about MATLAB? Anyway, read here:
William Rose
2022 年 10 月 23 日
The wording of your question, "...get the 95% confidence intervals for the true mean...", is thought-provoking. A strict interpretation of the p% confidence interval (X1,X2) is :
IF the true mean μ and true variance are what we estimate them to be ( and ), and if the variable has the distribution we think it has (and those are significant ifs), THEN, if we redo the sampling experiment many times, the sample mean, , will be between X1 and X2, p% of the time.
The corrollary, which is simpler to state and understand, is
There is a p% chance that the true mean lies within (X1,X2).
Some quibble a bit with the statement above, because the C.I. (X1,X2), which we estimated from a set of observations, either does (100%) or does not (0%) include the true mean - we just don't know if it does or doesn't. In this view, it is more correct to say
Confidence intervals constructed this way include the true mean p% of the time.
dpb
2022 年 10 月 23 日
"Confidence intervals constructed this way include the true mean p% of the time."
Again note the implied but left out for brevity is that the above is specifically true IFF the assumption of normality is also true.
BUT, the sample mean is also a statistic and by central limit theorem, a random sample of the means of estimates of the mean of any distribution will approach normality so the above is still liable to be ok even for at least moderately skewed distributions. But, if sample sizes are small (<=30 is a commonly used size), one should use the sample-size correction of substituting the t-distribution limits for normal z-points.
A page I just happened across does a pretty nice job here...<confidence_interval_of_a_mean_normal_approximation_method-principles-properties-assumptions>
the cyclist
2022 年 10 月 23 日
編集済み: the cyclist
2022 年 10 月 23 日
All of the above also assumes that the vector of 700 is a sample of a population, and we are trying to estimate the population mean.
:-)
I'll see myself out.
William Rose
2022 年 10 月 23 日
@dpb,
"I thought of going there, too, but for once was less wordy... :)"
Ha ha! I know you and @John D'Errico know all that CI stuff better than me - I just couldn't resist, I guess.
@Chris, you're welcome.
dpb
2022 年 10 月 23 日
It's probably time for @Chris to find the uni stastical consulting guru or his advisor and get more informed advice on his real problem. The basic rules are possible to be given, but to really know about applying to a specific problem one needs to know what the problem actually is.
John D'Errico
2022 年 10 月 23 日
At the very least, ask questions about statistics on a statistics forum.
回答 (0 件)
参考
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!エラーが発生しました
ページに変更が加えられたため、アクションを完了できません。ページを再度読み込み、更新された状態を確認してください。
Web サイトの選択
Web サイトを選択すると、翻訳されたコンテンツにアクセスし、地域のイベントやサービスを確認できます。現在の位置情報に基づき、次のサイトの選択を推奨します:
また、以下のリストから Web サイトを選択することもできます。
最適なサイトパフォーマンスの取得方法
中国のサイト (中国語または英語) を選択することで、最適なサイトパフォーマンスが得られます。その他の国の MathWorks のサイトは、お客様の地域からのアクセスが最適化されていません。
南北アメリカ
- América Latina (Español)
- Canada (English)
- United States (English)
ヨーロッパ
- Belgium (English)
- Denmark (English)
- Deutschland (Deutsch)
- España (Español)
- Finland (English)
- France (Français)
- Ireland (English)
- Italia (Italiano)
- Luxembourg (English)
- Netherlands (English)
- Norway (English)
- Österreich (Deutsch)
- Portugal (English)
- Sweden (English)
- Switzerland
- United Kingdom(English)
アジア太平洋地域
- Australia (English)
- India (English)
- New Zealand (English)
- 中国
- 日本Japanese (日本語)
- 한국Korean (한국어)