I want to compute FFT of each segments from a 102400 length signal, where I consider the length of segment is 1024. Than store the amplitude and freq n separate array

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I want to compute FFT of each segments from a 102400 length signal, where I consider the length of segment is 1024. Than store the amplitude and freq n separate array?
Data file is attached and store in v1.
I tried the below code :
requiredArray = [];
meanRequiredArray = [];
sum = 0;
count = 1;
for k = v1
requiredArray = [requiredArray, k];
disp(requiredArray);
if numel(requiredArray) == 3
meanRequiredArray = [meanRequiredArray, (abs(fft(requiredArray)))];
requiredArray = [];
end
disp(numel(requiredArray));
end
SA= meanRequiredArray';
  3 件のコメント
Rajeev Kumar
Rajeev Kumar 2022 年 10 月 11 日
Yes... stored Phase in seperate array
Matt J
Matt J 2022 年 10 月 11 日
編集済み: Matt J 2022 年 10 月 11 日
Then I think I have given you a valid answer below.

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回答 (1 件)

Matt J
Matt J 2022 年 10 月 11 日
編集済み: Matt J 2022 年 10 月 11 日
F=fft( reshape(input,1024,[]) ,[],1);
amplitude=abs(F);
phase=angle(F);

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