create cell array by extracting all the same row from multiple matrix

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Katherine Zheng
Katherine Zheng 2022 年 9 月 28 日
コメント済み: Stephen23 2022 年 10 月 1 日
I have three double A = [105x3]; B = [105x3]; C = [105x3]; I want to create a cell array D = {105 cells} each cells contains the corresponding rows from A B C.
For example,
D {1} = [
A(1,:);
B(1,:);
C(1,:);]
each row from A B C are in different rows in D
Is this achievable through cellfun?

採用された回答

Stephen23
Stephen23 2022 年 9 月 28 日
"Is this achievable through cellfun?"
Yes:
A = rand(105,3);
B = rand(105,3);
C = rand(105,3);
D = cellfun(@vertcat,num2cell(A,2),num2cell(B,2),num2cell(C,2), 'uni',0)
D = 105×1 cell array
{3×3 double} {3×3 double} {3×3 double} {3×3 double} {3×3 double} {3×3 double} {3×3 double} {3×3 double} {3×3 double} {3×3 double} {3×3 double} {3×3 double} {3×3 double} {3×3 double} {3×3 double} {3×3 double}
But most likely you should be using ND arrays rather than concatenating & splitting data like that.
  2 件のコメント
Stephen23
Stephen23 2022 年 10 月 1 日
"But I am not sure I understand the 'using ND arrays' in your suggestion."

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その他の回答 (1 件)

KSSV
KSSV 2022 年 9 月 28 日
編集済み: KSSV 2022 年 9 月 28 日
D = cell(105,5) ;
for i = 1:105
D{i} = [A(i,:) B(i,:) C(i,:)] ;
end
Or
D = [A B C] ;
D = num2cell(D,2) ;
  2 件のコメント
KSSV
KSSV 2022 年 9 月 28 日
cellfun uses loop inside.....

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