Extract value until regexp case match
1 ビュー (過去 30 日間)
I have this string. I was hoping to use regexp in order to extract the time and date embedded in this string. I was going to use regexp '.*?<=216', as prior to 216 is all the values I was hoping to extract. I was hoping that there would be an easy way to extract the date and time to a separate cell array. Thanks for any and all help.
"9/12/2022 7:38:51 PM
Stephen23 2022 年 9 月 23 日
Does the data you want to match always occur at the start of the string?
A = "9/12/2022 7:38:51 PM 216 Indicator";
B = regexp(A,'^\S+\s+\S+\s[AP]M','match','once')
T = datetime(B,'inputFormat','d/M/u h:m:s aa')