Why ifft results of analytic signal spectrum don't match with theoretical time formula?

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Dear all,
I need to convert a spectrum data back to time domain. Before it, I use a simple Gaussian pulse as a test. However, I found that results computed by ifft don't match with theoretical time equation. Why it happened? How to resolve it?
Fs=200;
T=1/Fs;
L=1200;
tau=0.4;
t0=2.8;
mag=10;
t=(0:L-1)*T;
f=Fs*(-L/2:L/2-1)/L;
Xf=@(x)sqrt(pi).*mag.*tau.*exp(-(2.*pi.*tau.*x).^2).*exp(-1i.*2.*pi.*x.*t0);
figure;
plot(f,real(Xf(f)));
% shift spectrum starting from 0 frequency
signal_comp=ifft(fftshift(Xf(f)).*L);
signal_theoretical=mag.*exp(-(t-t0).^2/tau^2);
figure;
plot(t,signal_theoretical);
hold on;
plot(t,real(signal_comp),'r--');

採用された回答

Matt J
Matt J 2022 年 9 月 22 日
編集済み: Matt J 2022 年 9 月 22 日
The IFFT and the continuous inverse Fourier transform are not the same thing.
tau=0.4;
t0=2.8;
mag=10;
Fs=200;
dT=1/Fs;
L=2000;
dF=1/dT/L;
f=dF*(-L/2:L/2-1);
t=dT*(-L/2:L/2-1);
Xf=@(x)sqrt(pi).*mag.*tau.*exp(-(2.*pi.*tau.*x).^2).*exp(-1i.*2.*pi.*x.*t0);
% shift spectrum starting from 0 frequency
signal_comp= fftshift(ifft(ifftshift(Xf(f))) ) /dT; %note factor of 1/dT
signal_theoretical=mag.*exp(-((t-t0)/2).^2/tau^2)/2; %fix the theoretical formula
figure;
plot(t(1:20:end),signal_theoretical(1:20:end),'o',...
t,real(signal_comp),'r--');
legend('Theoretical','Computed',location='northwest')
  1 件のコメント
Jiali
Jiali 2022 年 9 月 24 日
Thank you for your clarification! I do have misunderstanding between discrete Fourier transform and continuous Fourier transform although the concepts were taught before.

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