Using load for different files with varying names
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I have 25 files with .mat files, naming from data1 to data25
how to load them properly without manualy typing from 1 to 25
Here is my idea and the error
```
for i = 1:1:25
load('data%d.mat',i)
end
```
Error using load
Must be a text scalar.
0 件のコメント
採用された回答
Akira Agata
2022 年 9 月 13 日
How about the following?
for kk = 1:25
fileName = sprintf('data%d.mat', kk);
load(fileName)
%
% Some process for each file
%
end
2 件のコメント
Stephen23
2022 年 9 月 14 日
編集済み: Stephen23
2022 年 9 月 14 日
@Miraboreasu: Note that LOADing directly into the workspace often leads to problems processing the loaded data, exactly as your follow-up question indicates:
It is strongly recommended to LOAD into an output variable:
S = load(..)
and then access the fields of S.
Akira Agata
2022 年 9 月 14 日
Yes, of course it is recommended to load into an output variable, as you mentioned.
Thank you for your additional comment !
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