Condense code in Split string operation

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Sanju Das
Sanju Das 2022 年 9 月 13 日
編集済み: Sanju Das 2022 年 9 月 14 日
I have a excel file with the name 'xxx_yyy_zzz.xlsx'
Here, I want to extract only the part 'zzz' and for that I am using the following code
name = 'xxx_yyy_zzz.xlsx';
dummy1 = split('xxx_yyy_zzz.xlsx', '.');
dummy2 = split(dummy1{1}, '_');
final = dummy2{end};
My question is -- is it posible to condense these four lines into a single line of code?
Thanks
SD

採用された回答

Stephen23
Stephen23 2022 年 9 月 13 日
s = "xxx_yyy_zzz.xlsx";
regexp(s,'[^_.]+(?=\.)','match','once')
ans = "zzz"
  1 件のコメント
Sanju Das
Sanju Das 2022 年 9 月 14 日
編集済み: Sanju Das 2022 年 9 月 14 日
It works, thanks for the help

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その他の回答 (1 件)

Les Beckham
Les Beckham 2022 年 9 月 13 日
If you put the filename in a string instead of a char vector you can do it in one line
s = "xxx_yyy_zzz.xlsx"
s = "xxx_yyy_zzz.xlsx"
extractBetween(s, '_', '_')
ans = "yyy"
If it is a char vector it will take two lines
s = 'xxx_yyy_zzz.xlsx'
s = 'xxx_yyy_zzz.xlsx'
s1 = extractBetween(s, '_', '_')
s1 = 1×1 cell array
{'yyy'}
s2 = s1{:}
s2 = 'yyy'

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