Why does not string(f.name) work, f = dir(folder)?

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Simon
Simon 2022 年 8 月 17 日
コメント済み: Simon 2022 年 8 月 19 日
I want to do something to, like split, the filenames in a folder. I first use dir( ) to get the contents of the folder.
folder = "~/Documents"
f = dir(folder). % f is a structure
Though f.name looks like a cell array, however,
string(f.name)
% Error using string No constructor 'string'
% with matching signature found.'
I don't understand what that means. Your answer will help me learn to code with correct understanding.
cellfun(@string, f.name)
% Error using cellfun
% Input #2 expected to be a cell array, was char instead.
Does that mean f.name send its element to @string one by one, and cellfun expect to receive the whole cell array?
On the other hand, if I enclose f.name with { },
string({f.name}) % no error message

採用された回答

Stephen23
Stephen23 2022 年 8 月 17 日
編集済み: Stephen23 2022 年 8 月 17 日
"Why does not string(f.name) work, f = dir(folder)?"
Dot indexing into the structure f
f.name
generates a comma-separated list:
In the general case, this code
string(f.name)
will not work because it generates this comma-separated list:
string(f(1).name, f(2).name, .., f(end).name)
and STRING() is not defined for multiple input arguments like that. So clearly that syntax will not work.
"Though f.name looks like a cell array..."
It isn't a cell array, it is a comma-separated list. In contrast, this code:
{f.name}
generates one cell array from the comma-separated list, i.e. is equivalent to this:
{f(1).name, f(2).name, .., f(end).name}
and STRING() has no problem converting that cell array to a string array.
  2 件のコメント
Simon
Simon 2022 年 8 月 17 日
Thanks for your wonderful explanation and the links of further documentation. I quote from the help page
"Such a list, by itself, is not very useful. But when used with large and more complex data structures like MATLAB structures and cell arrays, the comma-separated list can enable you to simplify your MATLAB code."
I just did some code expriment with comma separated list. It seems to resemble what generator in Python does. After an element is processed, it is not stored in memory. That's why vectorization doesn't work with it (as in the case, string(f.name))), and for-loop works.
Stephen23
Stephen23 2022 年 8 月 17 日
編集済み: Stephen23 2022 年 8 月 17 日
"It seems to resemble what generator in Python does.
The whole point of the Python generator is that the elements do not exist in memory prior to being generated, but with the comma-separated list the elements already existed in memory and are not generated on the fly. The Python equivalent would be the asterisk operators, e.g. unpacking tuples and input arguments.
"After an element is processed, it is not stored in memory."
That rather depends on you, not on the comma-separated list syntax. You are welcome to discard the elements or store them (as my example with the cell array shows), or supply them as input arguments to any other suitable function/operator of your choice.

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その他の回答 (2 件)

KSSV
KSSV 2022 年 8 月 17 日
編集済み: KSSV 2022 年 8 月 17 日
folder = "~/Documents"
f = dir(folder) ; % f is a structure
for i = 1:length(f)
f(i).name
end
  1 件のコメント
Simon
Simon 2022 年 8 月 17 日
Thanks for your answer. Now I learn that vectorization does not work with comma separated list, but for-loop can be used to iterate over its elements.

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Steven Lord
Steven Lord 2022 年 8 月 17 日
filename = fullfile(matlabroot, 'toolbox', 'matlab', 'elfun', '*.m');
D = dir(filename)
D = 73×1 struct array with fields:
name folder date bytes isdir datenum
s = string({D.name});
Now you can operate on the elements of s.
s(1:4)
ans = 1×4 string array
"Contents.m" "abs.m" "acos.m" "acosd.m"
  1 件のコメント
Simon
Simon 2022 年 8 月 19 日
Lord, that is a wonderful answer. I want to add thanks for another thing. When I was using Python, I use pathlib a lot. It is a powerful, convenient package for handling folder related tasks. I had not expected Matlab to have similar functions. Here, you bring 'fullfile' to me. This makes the experience of switching from Python to Matlab very pleasant.

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