How to remove repeating elements but maintain occurrences in an array?
15 ビュー (過去 30 日間)
古いコメントを表示
Is there a way that I can get the first occurrence of consecutively repeating values, even if the same value occurs at few different places in the matrix?
Say I have a matrix
X=[2 2 2 2 -1 -1 -1 6 6 6 6 6 5 5 5 2 2 2 2 7 7 6 6]
I want the result to be
ans=[2 -1 6 5 2 7 6].
I've checked a similar question How to remove repeating elements from an array but using unique and keeping the same order as original matrix gives
ans=[2 -1 6 5 7].
I know I can use a loop like below. But I was wondering if there's a function for this.
for i=1:(length(X)-1)
if (X(i+1,6)-X(i,6))~=0
ans(i,1)=X(i+1,6);
else
ans(i,1)=NaN;
end
end
A function to do this will be great.
3 件のコメント
Image Analyst
2015 年 2 月 12 日
I would not use ans as the name of a variable - that has a special meeting in MATLAB.
採用された回答
Stephen23
2015 年 2 月 12 日
編集済み: Stephen23
2015 年 2 月 12 日
>> X=[2 2 2 2 -1 -1 -1 6 6 6 6 6 5 5 5 2 2 2 2 7 7 6 6];
>> Y = [true,diff(X)~=0];
>> X(Y)
ans = [2,-1,6,5,2,7,6]
This works well with integers. If you are working with floating point numbers, then you might need to include some kind of tolerance in the diff:
>> Y = [true,abs(diff(X))>tol];
その他の回答 (0 件)
参考
カテゴリ
Help Center および File Exchange で Matrices and Arrays についてさらに検索
製品
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!